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1 year ago

Analyze the diagram to answer the questions.

Mathematics

1 answer:

cluponka [151]1 year ago

3 0

The other name of angle ∠SAC is angle ∠CAS

<h3>How to illustrate the information?</h3>

T is point on ray AS

Given a ray diagram,

Ray RS is given and point A and T are on between R and S. It should be noted that another ray DC cuts the ray RS at point A.

One more ray given is AB. Angle SAC, we also write this angle in the form angle CAS.

Therefore, ∠SAC = ∠CAS.

Learn more about angle on:

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The point (8,k) lies on the line y=3x-5

Contact [7]

Answer:

x times 5 is 21

Step-by-step explanation:

you times x to 5 and then you will get 21

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4 years ago

Find the probability distribution for the following function: P(x)=x/2+1 for x=4,6, and 8

son4ous [18]

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3 years ago

Please help me someone

Brut [27]

Answer: C

Step-by-step explanation: Consider a triangle with points A, B and C. You must create a perpendicular bisector of AB and then a perpendicular bisector of BC that crosses each other. Then you must label the center of that point D, and then using a compass tool, create a circle around the triangle.

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2 years ago

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ms. wilson draws a model of the factorization of a polynomial with integer factors. her model is partially complete. which equat

Oliga [24]

I'll just factor the above equation.

x² + 18x + 80

x² ⇒ x * x
80
can be:
1 x 80
2 x 40
4 x 20
5 x 16
8 x 10 Correct pair

(x+8)(x+10)
x(x+10) +8(x+10) ⇒ x² + 10x + 8x + 80 = x² + 18x + 80

x+8 = 0
x = -8

x+10 = 0
x = -10

x = -8

(-8)² + 18(-8) + 80 = 0
64 - 144 + 80 = 0
144 - 144 = 0
0 = 0

(-10)² + 18(-10) + 80 = 0
100 - 180 + 80 = 0
180 - 180 = 0
0 = 0

I think the algebra tiles will not be a good tool to use to factor the quadratic equation because the equation is not a perfect square quadratic equation.

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3 years ago

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Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)

BigorU [14]

For a moment, let $y=x^2-2x+5$ . Then by the distributive property,

$(2x^2+4x-3)p=2x^2p+4xp-3p$

Again by the distributive property,

$2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2$

$4xp=4x(x^2-2x+5)=4x^3-8x^2+20x$

$-3p=-3(x^2-2x+5)=-3x^2+6x-15$

Taking everything together, we get

$(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)$
$(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15$

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3 years ago

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