HelpITS DUE TMR PLZ HELP AHHHHHHHHH
1 answer:
You might be interested in
Answer:
7.722 cm^2
Step-by-step explanation:
Step 1: Find the area of the square.
- Area of square = s^2, where s = side
- 6^2 = 36 cm^2
Step 2: Find the area of the circle.
- We are given the diameter of the circle as 6 cm, so the radius must be 3 cm.
- Area of circle is
, so now we plug in and simplify.
Step 3: Subtract area of circle from area of square.
Therefore, the area of the shaded region is 7.722 cm^2.
Have a lovely rest of your day/night, and good luck with your assignments! ♡
From the given figure ,
RECA is a quadrilateral
RC divides it into two parts
From the triangles , ∆REC and ∆RAC
RE = RA (Given)
angle CRE = angle CRA (Given)
RC = RC (Common side)
Therefore, ∆REC is Congruent to ∆RAC
∆REC =~ ∆RAC by SAS Property
⇛CE = CA (Congruent parts in a congruent triangles)
Hence , Proved
<em>Additional</em><em> comment</em><em>:</em><em>-</em>
SAS property:-
"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)
<u>also</u><u> </u><u>read</u><u> </u><u>similar</u><u> questions</u><u>:</u> Complete this proof. Given: EC AC, DB AC, ∠A = ∠F Prove: ΔMDF ∼ ΔNCA..
brainly.com/question/16250124?referrer
Consider the proof. Given: Segment AB is parallel to line DE. Prove: AD/DC = BE/EC What is the missing statement in Step 5? A.) AC = BC B.) AC/DC = BC/EC C.) AD...
brainly.com/question/11763540?referrer
