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4 years ago

Equation c squared - 10 c equal 0

Mathematics

1 answer:

bagirrra123 [75]4 years ago

8 0

Answer:

c = 0 or 10

Step-by-step explanation:

c² - 10c = 0

c(c - 10) = 0

c = 0 or c - 10 = 0

i.e c = 0 or 10

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A local hamburger shop sold a combined total of hamburgers and cheeseburgers on Thursday. There were fewer cheeseburgers sold th

myrzilka [38]

Answer:

the number of hamburgers sold on Thursday were 325.

Step-by-step explanation:

The total number of hamburger and cheese burger is missing

i will replace it with any figure, you can replace it wit your given data and you will get the solution.

A local hamburger shop sold a combined total of 593 hamburgers and cheeseburgers on Thursday

There were 57 fewer cheeseburgers sold than hamburgers

How many hamburgers were sold on thursday

Let h be the number of hamburgers and c be the number of cheeseburgers.

Using this information we can set up two equation as:

$h+c=593\\c=h-57$

Now we need to solve these two equations to get the value of number of hamburgers. For that we use substitution method as shown below:

$h+h-57=593\\2h-57=593\\2h=650\\h=325$

Therefore, the number of hamburgers sold on Thursday were 325.

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3 years ago

Find the slope of the line that passes through (20, -37) and (68, -56).

olya-2409 [2.1K]

i believe it would be -19/48

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3 years ago

13. ALGEBRA Arianna North borrowed $12,500 to purchase a new cello and

velikii [3]

8.1% is the exact interest rate

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3 years ago

4(3x^2y^4)^3 / (2x^3y^5)^4

tatyana61 [14]

Solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Step-by-step explanation:

We need to Solve the expression: $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

Solving:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

$=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}$

Another exponent rule says: $x^{-a}=\frac{1}{x^a}=$

$=\frac{27}{4x^{6}y^{8}}$

So, solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

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3 years ago

Use Green's Theorem to evaluate F · dr. C (Check the orientation of the curve before applying the theorem.)F(x, y) = y cos(x) −

Sergeeva-Olga [200]

Notice that C has a clockwise orientation. By Green's theorem, we have

$\displaystyle\int_C\mathbf F(x,y)\cdot\mathrm d\mathbf r=-\iint_D\left(\frac{\partial(xy+x\cos x)}{\partial x}-\frac{\partial(y\cos x-xy)}{\partial y}\right)\,\mathrm dx\,\mathrm dy$

where D is the triangule region with C as its boundary, given by the set

$D=\{(x,y)\mid0\le x\le2\land0\le y\le8-4x\}$

So we have

$\displaystyle\int_C\mathbf F(x,y)\cdot\mathrm d\mathbf r=-\int_0^2\int_0^{8-4x}((y+\cos x-x\sin x)-(\cos x-x\sin x))\,\mathrm dy\,\mathrm dx$

$\displaystyle\int_C\mathbf F(x,y)\cdot\mathrm d\mathbf r=-\int_0^2\int_0^{8-4x}y\,\mathrm dy\,\mathrm dx=\boxed{-\dfrac{64}3}$

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3 years ago

Equation c squared - 10 c equal 0​

Equation c squared - 10 c equal 0