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juin [17]
2 years ago
6

Find the area of the region (in square units) exact number

Mathematics
1 answer:
Margaret [11]2 years ago
3 0

The area of the region = area of the two rectangles = 64 units².

<h3>How to Find the Area of Rectangles?</h3>

A rectangle has a length and a width, and its area can be calculated using the formula below:

area of rectangle = (length)(width).

The region shown is composed of two rectangles. To find the area of the region, calculate the area of each of the rectangles in the image given.

Area of rectangle 1 = (length)(width)

Length = 12 units

Width = 4 units

Area of rectangle 1 = (12)(4)

Area of rectangle 1 = 48 units²

Area of rectangle 2 = (length)(width)

Length = 4 units

Width = 4 units

Area of rectangle 2 = (4)(4)

Area of rectangle 2 = 16 units²

The area of the region = area of the two rectangles = 48 + 16 = 64 units²

Learn more about the area of rectangle on:

brainly.com/question/25292087

#SPJ1

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Find the value of the expression (3x−12)−(12xy−10)(3x-12)-(12xy-10) for x=3x=3 and y=6y=6
Rina8888 [55]
Hi!

Put in the values for x and y.

(3 · 3 - 12)-(12 · 3 · 6 - 10)

Solve

(9 - 12)-(216 - 10)
-3 - 206
-209

The answer is -209

Hope this helps! :)

4 0
3 years ago
Read 2 more answers
Which graph represents the solution set of the equation 3y - x - 9 = 0?​
Arisa [49]

Answer:

Linear Graph

Step-by-step explanation:

7 0
3 years ago
An angle bisector of a triangle divides the opposite side of the triangle into segments 5 cm and 3 cm long. A second side of the
attashe74 [19]
There is a little-known theorem to solve this problem.

The theorem says that
In a triangle, the angle bisector cuts the opposite side into two segments in the ratio of the respective sides lengths.

See the attached triangles for cases 1 and 2.  Let x be the length of the third side.

Case 1:
Segment 5cm is adjacent to the 7.6cm side, then
x/7.6=3/5  => x=7.6*3/5=4.56 cm

Case 2:
Segment 3cm is adjacent to the 7.6 cm side, then
x/7.6=5/3 => x=7.6*5/3=12.67 cm

The theorem can be proved by considering the sine rule on the adjacent triangles ADC and BDC with the common side CD and equal angles ACD and DCB.

6 0
3 years ago
3. Combine terms: 123a + 26b -4b – 16a.
m_a_m_a [10]

Answer:C) -4a+22b because u add 12a ➕-16a and u get negative 4 then u mines 26b-4b and u get 22

Step-by-step explanation:

6 0
3 years ago
Help me solving number 22 &amp; 24. Thanks:)
aksik [14]

Answer:

Question 22

x intercept is 7

y intercept is 4

The answer is C

Question 24

x intercept is -4

y intercept is 7

The answer is B

Step-by-step explanation:

x and y intercepts are the points at which the graph meets x and y axes.

x and y intercepts can be found the following way,

y intercept - substitute 0 to x

x intercept - substitute 0 to y

Question 22

7y=28-4x

Substitute x=0 to find the y intercept

7y=28-4*0

=7y=28

=y=4

Substitute y=0 to find x intercept

7*0=28-4x

=0=28-4x

=4x=28

=x=7

Therefore,

x intercept is 7

y intercept is 4

The answer is C

<u>Question 24</u>

4y=7x+28

Substitute x=0 to find the y intercept

4y=7*0+28

=4y=28

=y=7

Substitute y=0 to find x intercept

4*0=7x+28

=0=7x+28

=-7x=28

=x=-4

Therefore,

x intercept is -4

y intercept is 7

The answer is B


5 0
3 years ago
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