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2 years ago

Which value is a solution for the equation tan/2=-1

Mathematics

1 answer:

erma4kov [3.2K]2 years ago

6 0

The value of the solution is 3π/2.

What is a trigonometric equation?

An equation involving one or more trigonometric ratios of unknown angles is called a trigonometric equation.

tan x/2 = -1

tanx/2 = tan(-π/4)

tanx=tanФ

⇒ The general equation of tanx=tanФ is

⇒ x=nπ+Ф

x/2=nπ+(-π/4)

at n=0

x/2=-π/4

x=-π/2

at n=1

x/2=π-π/4

x/2=3π/4

x=3π/2

learn more about trigonometric equations here :

brainly.com/question/2088730

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Questions: Which value is a solution for the equation tan x/2 = -1?

A. 5pi/4

B. 7pi/4

C. 3pi/4

D. 3pi/2

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8.84 ×10⁻¹

Step-by-step explanation:

Move one decimal to the right to make one number go after the decimal. (ONLY one number from 0 - 9)

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3 years ago

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Step-by-step explanation:

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3 years ago

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3 years ago

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Help me?! Will give 20 points!

jeyben [28]

58 to x should be the ratio of 6/3 or 1/2 if they are similar.

Find out how much bigger 58 is compared to 6, the matching side on the other polygon.

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3 years ago

A group of retailers will buy 104 televisions from a wholesaler if the price is $300 and 144 if the price is $250. The wholesale

const2013 [10]

Answer:

(275,122)

When the price will be $275, the quantity will be 122 televisions.

Step-by-step explanation:

We have been given that a group of retailers will buy 104 televisions from a wholesaler if the price is $300 and 144 if the price is $250.

As the quantity of televisions depends on price of televisions, so our demand curve will pass through points (300,104) and (250,144).

Let us find slope of demand line using slope formula.

$m=\frac{y_2-y_1}{x_2-x_1}$ , where,

$m =\text{Slope of line}$ ,

$y_2-y_1=\text{Difference between two y-coordinates}$ ,

$x_2-x_1=\text{Difference between same x-coordinates of two y-coordinates}$

Upon substituting coordinates of our given points in slope formula we will get,

$m=\frac{104-144}{300-250}$

$m=\frac{-40}{50}$

$m=-\frac{4}{5}$

Let us substitute $m=-\frac{4}{5}$ coordinates of point (250,144) in slope intercept form of equation ( $y=mx+b$ ).

$144=-\frac{4}{5}*250+b$

$144=-4*50+b$

$144=-200+b$

$144+200=-200+200+b$

$344=b$

Upon substituting $b=344$ and $m=-\frac{4}{5}$ we will get equation of our demand line as:

$y=-\frac{4}{5}x+344$

Similarly we will find the equation of supply line using points (225,88) and (315,168).

$m=\frac{168-88}{315-225}$

$m=\frac{80}{90}$

$m=\frac{8}{9}$

Let us substitute $m=\frac{8}{9}$ and coordinates of point (225,88) in slope intercept form of equation ( $y=mx+b$ ).

$88=\frac{8}{9}*225+b$

$88=8*25+b$

$88=200+b$

$88-200=200-200+b$

$-112=b$

Upon substituting $b=-112$ and $m=\frac{8}{9}$ we will get equation of our supply line as:

$y=\frac{8}{9}x-122$

Let us equate both lines to find the point where both lines intersect.

$-\frac{4}{5}x+344=\frac{8}{9}x-122$

$-\frac{4}{5}x-\frac{8}{9}x+344=\frac{8}{9}x-\frac{8}{9}x-122$

$-\frac{4}{5}x-\frac{8}{9}x+344=-122$

$-\frac{4}{5}x-\frac{8}{9}x+344-344=-122-344$

$-\frac{4}{5}x-\frac{8}{9}x=-466$

Let us have a common denominator.

$-\frac{4*9}{5*9}x-\frac{8*5}{9*5}x=-466$

$-\frac{36}{45}x-\frac{40}{45}x=-466$

$\frac{-36-40}{45}x=-466$

$\frac{-76}{45}x=-466$

$\frac{-76}{45}*\frac{45}{-76}x=-466*\frac{45}{-76}$

$x=466*\frac{45}{76}$

$x=6.1315789473684211*45$

$x=275.9210526315789495\approx 275$

Let us substitute x=275 in any of our equation to solve for y.

$y=-\frac{4}{5}*275+344$

$y=-4*55+344$

$y=-220+344$

$y=122$

Therefore, the equilibrium point for the market will be (275,122).

5 0

3 years ago