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n200080 [17]
3 years ago
10

Anya is saving her allowance to purchase a bike. Anya started her savings with $10 and is saving $5 per week. Let y represent th

e total amount Anya has saved and x represent the number of weeks Anya has been saving.
Select two points to graph the line.
Question 8 options:
(0, 0) and (15, 10)
(0, 10) and (1, 15)
(0, 15) and (1, 10)
(0, 0) and (10, 15)
Mathematics
2 answers:
zysi [14]3 years ago
5 0

Anya is saving her allowance to purchase a bike.Anya started her savings with $10 and is saving $5 per week.Let y represent the total amount Anya has saved and x represent the number of weeks Anya has been saving. Hope this helped :)
ladessa [460]3 years ago
3 0

Answer: The answer for this question would be answer choice B "(0, 10) and (1, 15)". (0, 10) represents her starting amount and week saved, and (1, 15) would represent her saving for one week and having $15 total.

Hope this helps!

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You need a 25% alcohol solution. On hand, you have a 225 mL of a 35% alcohol mixture. How much pure water will you need to add t
Radda [10]

You will need 252 mL of pure water to obtain 0.25 mL of the desired 25% solution.

If we add X amount of water to the solution, the total amount of solution is 375+X.

And that must be 25%.

<h3>What is the amount of solute in the current solution?</h3>

The amount of solute in the current amount of solution is

0.6(375)=225.

That amount won't change by adding water.

So we set up the equation so that the amount of solute divided by the new total amount of solution equals 25%.

225/(375+X)=0.25

cross multiply and solve

225/0.25=(375+X)

900-375=X

X=525

The pure water will you need to add to obtain the desired solution is 525.

Then we check 225/(375+525)=0.25.

To learn more about the mixture problem visit:

brainly.com/question/24647756

#SPJ1

7 0
2 years ago
mr. Rose asked his student to draw a quadrilateral with four unequal sides.draw An example of this kind of quadrilateral
polet [3.4K]

Answer:

Follow the followings steps to draw a quadrilateral with 4 unequal sides:

Step 1 : Draw line \overline {AB}  of length 10cm.

Step 2 : Construct 90° angle on \overline {AB}   with A as vertex and mark an arc of 5 cm on new arm of right angle. That's Point D.

Step 3 : Again Construct 90° angle on  \overline {AD} with D as vertex.

Step 4 : Mark an arc of length 6 cm on arm of 2nd right angle. Mark that point as C.

Step 5 : To complete the Quadrilateral, Join Point C and B.

A Quadrilateral (Specially mentioned Trapezoid) ABCD with four unequal side is constructed.  

4 0
3 years ago
A quadratic function has a maximum point. It cuts the y axis at y = − 4 and the x axis at x = 1 and at x = 5. The x coordinate o
Irina-Kira [14]

Answer: X= 4

Step-by-step explanation:

7 0
3 years ago
Ok, last one I promise.
Papessa [141]
All of them, so 10.
Check the key to see how to read it. 1 | 7 would be 17. So the number of pairs in each store are:
17, 18, 20, 25, 28, 34, 34 37, 38, and 40 (all below 60)
4 0
3 years ago
Pls help quick i need this
irina [24]

Answer:

See explanation

Step-by-step explanation:

Q1-5.

1. Plane parallel to WXT is ZYU.

2. Segments parallel to \overline {VU} are \overline {ZY}, \overline {WX} and \overline {ST}

3. Segments parallel to \overline {SW} are \overline {VZ}, \overline {YU} and \overline {XT}

4. Segments skew to \overline {}\overline {XY} are \overline {SV} and \overline {VZ} (not lie in the same plane and not parallel)

5. Segments skew to \overline {}\overline {VZ} are \overline {WX} and \overline {XT} (not lie in the same plane and not parallel)

Q6.

a. \angle 4 and \angle 10 are the same-side interior angles, transversal k

b. \angle 8 and \angle 11 are alternate exterior angles, transversal m

c. \angle 1 and \angle 4 do not form any pair of angles

d. \angle 2 and \angle 12 are the same-side exterior angles, transversal  k

e. \angle 5 and \angle 7 are corresponding angles, transversal  j

f. \angle 2 and \angle 13 are alternate interior angles, transversal l

Q7.

m\angle 1=m\angle 7=131^{\circ} (as vertical angle with angle 7)

m\angle 2=180^{\circ}-131^{\circ}=49^{\circ} (as supplementary angle with angle 1)

m\angle 8=49^{\circ} (as vertical angle with angle 2)

m\angle 3=m\angle 1=131^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal r)

m\angle 4=m\angle 2=49^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal r)

m\angle 5=m\angle 7=131^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal r)

m\angle 6=m\angle 8=49^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal r)

m\angle 10=m\angle 16=88^{\circ} (as vertical angle with angle 16)

m\angle 9=180^{\circ}-88^{\circ}=92^{\circ} (as supplementary angle with angle 16)

m\angle 15=92^{\circ} (as vertical angle with angle 9)

m\angle 14=m\angle 16=88^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal s)

m\angle 13=m\angle 15=92^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal s)

m\angle 12=m\angle 10=88^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal s)

m\angle 11=m\angle 9=92^{\circ} (as corresponding angles when parallel lines p and q are cut by transversal s)

Q8.

m\angle 7=m\angle 9=105^{\circ} (as vertical angles)

m\angle 8=180^{\circ}-105^{\circ}=75^{\circ} (as supplementary angle with angle 9)

m\angle 10=m\angle 8=75^{\circ} (as vertical angles)

m\angle 6=m\angle 8=75^{\circ} (as alternate interior angles when parallel lines a and b are cut by transversal c)

m\angle 1=180^{\circ}-75^{\circ}-63^{\circ}=42^{\circ} (by angle addition postulate)

m\angle 3=180^{\circ}-42^{\circ}-63^{\circ}=75^{\circ} (by angle addition postulate)

m\angle 4=m\angle 1=42^{\circ} (as vertical angles)

m\angle 5=m\angle 2=63^{\circ} (as vertical angles)

m\angle 11=m\angle 4=42^{\circ} (as alternate interior angles when parallel lines a and b are cut by transversal d)

m\angle 12=180^{\circ}-42^{\circ}=138^{\circ} (as supplementary angles)

m\angle 13=m\angle 11=42^{\circ} (as vertical angles)

m\angle 14=m\angle 12=138^{\circ} (as vertical angles)

3 0
3 years ago
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