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3 years ago

1,00+ 1,00+2,00+3,00+4_00

Mathematics

1 answer:

Flura [38]3 years ago

4 0

Well you would have to fill in the bank so it would be 4000 and the answer would be 11,000

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30 POINTS!!!!! WILL MARK BRAINLST!

bazaltina [42]

Answer:

Reduction

Step-by-step explanation:

3 0

3 years ago

What is the exponential form of the logarithmic equation? 4=log0.8 0.4096

Advocard [28]

The exponential form of this equation is "0.8⁴ = 0.4096 ".

Now, in this logarithm equation the base of the log is 0.8.
when we convert this equation to exponential form 0.8 will go to left side, 4 moved up and became the exponent of 0.8 and thus it makes the exponential equation;
4=log₀.₈ 0.4096 logarithmic equation

0.8⁴ = 0.4096 exponential form

6 0

3 years ago

Find the exact value of sin(cos^-1(4/5))

boyakko [2]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2762144

_______________

Let $\mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}$

$\mathsf{0\le \theta\le\pi,}$ because that is the range of the inverse cosine funcition.

Also,

$\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}$

Square both sides and apply the fundamental trigonometric identity:

$\mathsf{(5\,cos\,\theta)^2=4^2}\\\\
\mathsf{5^2\,cos^2\,\theta=4^2}\\\\
\mathsf{25\,cos^2\,\theta=16\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{25\cdot (1-sin^2\,\theta)=16}$

$\mathsf{25-25\,sin^2\,\theta=16}\\\\
\mathsf{25-16=25\,sin^2\,\theta}\\\\
\mathsf{9=25\,sin^2\,\theta}\\\\
\mathsf{sin^2\,\theta=\dfrac{9}{25}}
$

$\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{9}{25}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{3^2}{5^2}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{3}{5}}$

But $\mathsf{0\le \theta\le\pi,}$ which means $\theta$ lies either in the 1st or the 2nd quadrant. So $\mathsf{sin\,\theta}$ is a positive number:

$\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\
\therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: inverse trigonometric function cosine sine cos sin trig trigonometry

3 0

3 years ago

Read 2 more answers

Fred is playing tennis. For every 2 of his serves that land in, 4 serves land out. If he hit 28 serves in, how many serves lande

bija089 [108]

2 for every 4 = 1 for every two, so 28 multiplied by two. Your answer is 56.

5 0

3 years ago

Read 2 more answers

A door of a lecture hall is in a parabolic shape. The door is 56 inches across at the bottom of the door and parallel to the flo

Arada [10]

Answer:

The parabolic shape of the door is represented by $y - 32 = -\frac{2}{49}\cdot x^{2}$ . (See attachment included below). Head must 15.652 inches away from the edge of the door.

Step-by-step explanation:

A parabola is represented by the following mathematical expression:

$y - k = C \cdot (x-h)^{2}$

Where:

$h$ - Horizontal component of the vertix, measured in inches.

$k$ - Vertical component of the vertix, measured in inches.

$C$ - Parabola constant, dimensionless. (Where vertix is an absolute maximum when $C < 0$ or an absolute minimum when $C > 0$ )

For the design of the door, the parabola must have an absolute maximum and x-intercepts must exist. The following information is required after considering symmetry:

$V (x,y) = (0, 32)$ (Vertix)

$A (x, y) = (-28, 0)$ (x-Intercept)

$B (x,y) = (28. 0)$ (x-Intercept)

The following equation are constructed from the definition of a parabola:

$0-32 = C \cdot (28 - 0)^{2}$

$-32 = 784\cdot C$

$C = -\frac{2}{49}$

The parabolic shape of the door is represented by $y - 32 = -\frac{2}{49}\cdot x^{2}$ . Now, the representation of the equation is included below as attachment.

At x = 0 inches and y = 22 inches, the distance from the edge of the door that head must observed to avoid being hit is:

$y -32 = -\frac{2}{49} \cdot x^{2}$