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2 years ago

Will give crown thanks

Mathematics

2 answers:

Tatiana [17]2 years ago

8 0

Answer:

A is right

B is acute

C is obtuse

D is right

Step-by-step explanation:

90 is right

anything under 90 is acute

over 90 obtuse

Anuta_ua [19.1K]2 years ago

3 0

Answer:

∠A: Right Angle.

∠B: Acute Angle.

∠C: Obtuse Angle.

∠D: Right Angle.

<u>I hope this helped you </u>

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Tom throws a ball into the air. The ball travels on a parabolic path represented by the equation , where represents the height o

tigry1 [53]

Answer:

2.5 second

Step-by-step explanation:

The equation is missing in the question.

The equation is, $h=-8t^2+40t$ , where 'h' is the height and 't' is time measured in second.

Now we know to reach its maximum height, h in t seconds, the derivative of h with respect to time t is given by :

$\frac{dh}{dt} =0$

Now the differentiating the equation with respect to time t, we get

$\frac{dh}{dt}=\frac{d}{dt}(-8t^2+40t)$

$\frac{dh}{dt}=-16t+40$

For maximum height, $\frac{dh}{dt} =0$

So, $-16t+40=0$

$\Rightarrow 16t=40$

$\Rightarrow t=\frac{40}{16}$

$\Rightarrrow t = 2.5$

Therefore, the ball takes 2.5 seconds time to reach the maximum height.

7 0

3 years ago

What is the slope of the line that passes through the points (1, 7) and (10, 1)?

Vaselesa [24]

I will need a picture

4 0

2 years ago

If a drug has a concentration of 8.22 mg per 3.039 mL, how many mL are needed to give 7.469 gram of the drug? Round to 1 decimal

aalyn [17]

Answer:

2.8 litres

Step-by-step explanation:

8.22 mg per 3.039 mL

2.704 mg per 1 mL

7.469 gram = 7469 milligrams

7469 milligrams per 2,761.34927mL

= 2.761 litres = 2.8 litres

7 0

3 years ago

Find the zeros of polynomial x^2-3

Yakvenalex [24]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The required zeroes are ~

$\boxed{ \boxed {\sqrt{3}} \: \: and \: \: \boxed{- \sqrt{3} }}$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Let's equate the given polynomial with 0, to find its roots ~

that is ~

${x}^{2} - 3 = 0$

${x}^{2} - ( \sqrt{3} ) {}^{2} = 0$

$(x + \sqrt{3} )(x - \sqrt{3} ) = 0$

there are two cases,

Case # 1 - when (x + √3) = 0

$x + \sqrt{3} = 0$

$x = - \sqrt{3}$

and

Case # 2 - when (x - √3) = 0

$x - \sqrt{3} = 0$

$x = \sqrt{3}$

4 0

2 years ago

Read 2 more answers

A 5.8-ft-tall person walks away from a 9-ft lamppost at a constant rate of 3.4 ft/sec. What is the rate that the tip of the pers

Dovator [93]

Answer:

9.56 ft/sec

Step-by-step explanation:

We are told that a 5.8-ft-tall person walks away from a 9-ft lamppost at a constant rate of 3.4 ft/sec.

I've attached an image showing triangle that depicts this;

Thus; dx/dt = 3.4 ft/sec

From the attached image and using principle of similar triangles, we can say that;

9/y = 5.8/(y - x)

9(y - x) = 5.8y

9y - 9x = 5.8y

9y - 5.8y = 9x

3.2y = 9x

y = 9x/3.2

dy/dx = 9/3.2

Now, to find how fast the tip of the shadow is moving away from the lamp post, it is;

dy/dt = dy/dx × dx/dt

dy/dt = (9/3.2) × 3.4

dy/dt = 9.5625 ft/s ≈ 9.56 ft/sec

5 0

3 years ago