Question

A prism and two nets are shown below:

Answer 1

A) Net A is correct. The right angles are at opposite ends of the same line. Not so in Net B..

B) AB = 3, BC = 5, CD = 8.6

C) The central rectangle has length 3+4+5 = 12, and width CD = 8.6. Its area is
.. Arect = (12 in)*(8.6 in) = 103.2 in^2

The two triangles ABC form a rectangle that is 3x4, so has area
.. Atriangles = (3 in)*(4 in) = 12 in^2

The total surface area is (103.2 +12) in^2 = 115.2 in^2.

Answer 2

A) Net A would be the correct net for the prism.

B) AB = 3in
BC = 5in
CD = 8.6in

C) area of one triangle : 4*3/2 = 6
But there's 2 triangles so 6*2 = 12cm2
Area of the middle square : 8.6*4 = 34.4cm2
Area of bottom square : 8.6*5 = 43cm2
Area of top rectangle : 8.6*3 = 25.8cm2

Finally add all of these areas together and you will get the surface area : 115.2cm