A crowbar 29 in. long is pivoted 6 in. from the end. What force must be applied at the long end in order to lift a 700 Ib object

Question

1 year ago

12

at the short end?

1 answer:

Alla [95] · Answer 1 · 2023-12-03T20:19:39+03:00

A force of 182.6 lb should be applied to lift 700 lb object.

<h3>How to calculate the force?</h3>

Let the force required to lift be F

Total length = 29 in.

Distance of short end from pivot = in.

Distance from long end = 29-6 = 23 in.

Now Equating moments

F × 23 = 700x6

23F = 4200

F = 4200/23

= 182.6 lb

A force of 182.6 lb should be applied to lift 700 lb object.

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