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Tpy6a [65]
2 years ago
11

Dianna has 7 quarters, 3 dimes, and 8 nickels in her purse. She reaches into her purse and randomly grabs two coins. What is the

probability that Dianna grabs a dime first and then a nickel?
Mathematics
1 answer:
Leni [432]2 years ago
4 0

There are 18 coins total in her bag:

7+3+8=18coins

3 of the 18 coins are dimes, so the odds of first drawing a dime are 3/18

P(dime)=3/18

Since the nickel was taken out and not replaced, there are now 17 coins in her purse.

18-1=17coins

8 of the 17 remaining coins are nickels, so the odds of drawing a nickel are 8/17.

P(nickel)=8/17


Now we multiply the two probabilities by eachother to find out the odds of both occurring...


P(dime)*P(nickel)=

3/18*8/17=24/306=8/103=0.078=8%

The probability of grabbing a dime and then a nickel are 8/103 or 0.078 or an 8% chance, whichever way you'd prefer to write it.

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Answer:

50 minutes

Step-by-step explanation:

1600 - 12m = 2000 - 20m

8m = 400

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Place value of digit 3 in number 60425321
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Answer:

HUNDREDS

Step-by-step explanation:

7 0
3 years ago
Can anyone identify the two variables
valentina_108 [34]
The two variables are time (x) and distance (y)

And the answer is they will meet after 1 mile

The function of the aunt and uncle is y=25x+5

The function of yourself is y2=30x

Since you want to know when you’ll meet, you just resolve y=y2 or 25x+5=30x

Wich will be x=1 so 1 mile
8 0
2 years ago
Cx=r/d<img src="https://tex.z-dn.net/?f=%5Cfrac%7Br%7D%7Bd%7D" id="TexFormula1" title="\frac{r}{d}" alt="\frac{r}{d}" align="abs
antoniya [11.8K]

Answer:

x=\frac{rc}{d}

Step-by-step explanation:

ill take the equation as this

cx=\frac{r}{d}

divide both side by c

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{\frac{b}{c}}=\frac{a\cdot \:c}{b}

Next time when you see someone greif your question, please report it.

Shame for the other guy

Hoped this helped you

Red

8 0
2 years ago
Two college instructors are interested in whether or not there is any variation in the way they grade math exams. They each grad
AlekseyPX

Answer:

Since the calculated value of F = 1.4397 is less than the critical value of

F (9,9)= 2.4403 we conclude that the  first instructor's variance is smaller and reject H0.

Step-by-step explanation:

1)Formulate the hypothesis that first variance is equal or greater than the second variance

H0: σ₁²≥σ₂²  against the claim  that the first instructor's variance is smaller

 Ha: σ₁²< σ₂²

2) Test Statistic F= s₂²/s₁²

F= 84.8/ 58.9=  1.4397

3)Degrees of Freedom = n1-1= 10-1= 9  and n2 = 10-1= 9

4)Critical value   at 10 % significance level= F(9,9)= 2.4403

5)Since the calculated value of F = 1.4397 is less than the critical value of

F (9,9)= 2.4403 we conclude that the  first instructor's variance is smaller and reject H0.

4 0
3 years ago
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