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4vir4ik [10]
2 years ago
6

What is the equation of a line parallel to y=1/2×+6 that passes through (-4,1)

Mathematics
1 answer:
IgorC [24]2 years ago
5 0

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{2}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so we're really looking for the equation of a line whose slope is 1/2 and passes through (-4 , 1)

(\stackrel{x_1}{-4}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{ \cfrac{1}{2}}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-1=\cfrac{1}{2}(x+4)\implies y-1=\cfrac{1}{2}x+2\implies y=\cfrac{1}{2}x+3

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Answer:

a₈ = 37

Step-by-step explanation:

The given arithmetic sequence is: 3, 8, 13, 18, 23, . . .

The recursive formula for the sequence is: $ a_n = a_{n - 1} + 5 $

Here, $ a_n $ represents the $ n^{th} $ of the sequence.

And, $ a_{n - 1} $ represents the $ (n - 1)^{th} $ of the sequence.

'+5' denotes that '5' is added to the $ (n - 1)^{th} $ term to get the $ n^{th} $ term. In other words, the difference between two consecutive numbers in the sequence is 5.

Now, we are asked to find a₈ i.e., n =8.

Substituting in the recursive formula we get: a₈ = a₍₈₋ ₁₎ + 5 = a₇ + 5.

So, to determine a₈ we need to know a₇. From the sequence we see that a₅ = 23.

⇒ a₆ = 23 + 5 = 28.

⇒ a₇ = 28 + 5 = 32.

⇒ a₈ = 32 + 5 = 37.

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Step-by-step explanation:

<em><u>Simplify:</u></em>

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<u><em>((−4)3)2 </em></u>

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<u><em>=4096</em></u>

<u><em /></u>

Answer: 4096

<em><u>Hope this helps.</u></em>

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