All categories

1 year ago

I think it’s either a or b?? Does anyone know?? Pls help me!!

Mathematics

2 answers:

bogdanovich [222]1 year ago

8 0

Answer:

Step-by-step explanation:

I did the math i learned a few years ago and i got the answer A

Murljashka [212]1 year ago

3 0

Solution we have
The triangular prism in which
Let Sp = 16., S2 = 10,83 = 10 Now, L=
12 cm
then, we know that,
lateral surface area of
Triangular prism = L (S, +S, +S2)
= (16+10+10)/12)
Hence, the correct. option A is correct

You might be interested in

Solve for v.<br><br> M=bv/k<br><br> Please help!!! I'm horrible at math.

Semenov [28]

First, I like switching the sides so that the equation looks like this: bv/k=M
Then get bv alone by multiplying both sides by k: bv=kM
After that, divide both sides by b to get v by itself: <u>v=kM/b</u>
I hope this helps you!

7 0

3 years ago

Which shows the factored form of x2 – 12x – 45? (x 3)(x – 15) (x – 3)(x – 15) (x 3)(x 15) (x – 3)(x 15).

Aleksandr [31]

The factors of the quadratic equation are (x+3) and (x-15).

<h2 /><h2>Given to us</h2>

$x^2-12x-45\\$

The factors of $x^2-12x-45\\$ .

<h3 /><h3>Solution</h3>

$x^2-12x-45\\$

As we can see in the quadratic equation the value of ac is -45x². therefore, we need to divide -12x into two parts such that their sum must give -12x and their product gives us -45x².

therefore, dividing -12x into -15x and 3x,

$x^2-15x+3x-45\\$

Taking common out,

$x^2-15x+3x-45\\x(x-15)+3(x-15)\\(x+3)(x-15)$

Hence, the factors of the quadratic equation are (x+3) and (x-15).

Learn more about quadratic equations:

brainly.com/question/2263981

3 0

2 years ago

A man that is 6 feet tall casts a shadow 5 feet long. At the same time, a lamppost beside the man casts a shadow 25 feet long. H

Montano1993 [528]

Answer:

The answer to your question is: L = 30 ft

Step-by-step explanation:

Data

man = 6 ft

man shadow = 5 ft

lamppost shadow = 25 ft

lamppost height = ? = L

Process

$\frac{6}{5} = \frac{L}{25}$

$L = \frac{6 x 25}{5}$

$L = \frac{150}{5}$

L = 30 ft

5 0

3 years ago

Tan(2 sin^-1 0.4)<br> Find the Exact value

stiv31 [10]

Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

Note:

0.84=0.04(21)

So the principal square root of 0.04 is 0.2

Sqrt(0.84)=0.2sqrt(21).

tan(2u)=[(20)(0.2)(sqrt(21)]/[17]

tan(2u)=[(20)(2)sqrt(21)]/[170]

tan(2u)=[(2)(2)sqrt(21)]/[17]

tan(2u)=[4sqrt(21)]/[17]

7 0

3 years ago

In a clinical study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability th

MrRa [10]

Answer:

a) 0.984

b) 20 people

Step-by-step explanation:

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

$\frac{20!}{18!2!}=190$

In this 190 20-tuples there are only 3 where the 2 carriers of the gene are in the first 3 places, namely

(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

4 0

3 years ago