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Natali [406]
2 years ago
11

What is the y-intercept of f(x) = 3x+2?

Mathematics
1 answer:
Natalka [10]2 years ago
5 0

Answer:

The y-intercept of f(x) = 3x+2 is 2

Step-by-step explanation:

To find the y-intercept, substitute 0 for x and solve for y.

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G(-3) if g(x)=2x-4 show your work
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Answer:

g(-3) = -10

Step-by-step explanation:

All you have to do is plug -3 in for x!

g(-3) = 2(-3) - 4

g(-3) = -6 - 4

g(-3) = -10

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The only way to identify an intercept is as an ordered pair.<br><br> True<br> False
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False because there are other ways to identify an intercept
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Write 2.05 × 10^5 without exponents.
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3 years ago
Given the graph of a function f. Identify the function by name. Then Graph, state domain &amp; range in set notation:A) f(x) +2B
WARRIOR [948]

The function in the graph has the name of square function.

The domain of a function is all values of x the function can have. The domain of this function is all real numbers:

\mleft\lbrace x\in\R\mright\rbrace

The range of a function is all values of y the function can have. The range of this function is all positive numbers, including zero:

\mleft\lbrace y\in\R\mright|y\ge0\}

In order to graph f(x) + 2, we just need to translate the graph 2 units up. To find the new points, we need to increase all y-coordinates by 2:

(-2, 6), (-1, 3), (0, 2), (1, 3), (2, 6)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ 2}

Then, in order to graph f(x) - 2, we just need to translate the graph 2 units down. To find the new points, we need to decrease all y-coordinates by 2:

(-2, 2), (-1, -1), (0, -2), (1, -1), (2, 2)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ -2}

4 0
9 months ago
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