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OlgaM077 [116]
2 years ago
12

each of exercises 15–30 gives a function ƒ(x) and numbers l, c, and e 7 0. in each case, find an open interval about c on which

the inequality 0 ƒ(x) - l 0 6 e holds. then give a value for d 7 0 such that for all x satisfying 0 6 0 x - c 0 6 d the inequality 0 ƒ(x) - l 0 6 e hol
Mathematics
1 answer:
3241004551 [841]2 years ago
6 0

The given inequality holds for the open interval (2.97,3.03)

It is given that

f(x)=6x+7

cL=25

c=3

ε=0.18

We have,

|f(x)−L| = |6x+7−25|

          = |6x−18|

          = |6(x−3)|

          = 6|x−3|

Now,

6|x−3| <0.18  then |x−3|<0.03 ----->−0.03<x-3<0.03---->2.97<x<3.03

the given inequality holds for the open interval (2.97,3.03)

For more information on inequality click on the link below:

brainly.com/question/11613554

#SPJ4

Although part of your question is missing, you might be referring to this full question: For the given function f(x) and values of L,c, and ϵ0, find the largest open interval about c on which the inequality |f(x)−L|<ϵ holds. Then determine the largest value for δ>0 such that 0<|x−c|<δ→|f(x)−|<ϵ.

f(x)=6x+7,L=25,c=3,ϵ=0.18

 

.

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notka56 [123]

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Step-by-step explanation:

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4 0
3 years ago
Which statements about the function are true? Select two
iogann1982 [59]

Answer:

The vertex of the function is at (1,-25)

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one.

<em>Part of the graph of the function f(x) = (x + 4)(x-6) is shown  below. </em>

<em>Which statements about the function are true? Select two </em>

<em>options. </em>

<em>The vertex of the function is at (1,-25). </em>

<em>The vertex of the function is at (1,-24). </em>

<em>The graph is increasing only on the interval -4< x < 6. </em>

<em>The graph is positive only on one interval, where x <-4. </em>

<em>The graph is negative on the entire interval  </em>

My answer:

Given the factored form of the function:

f(x) = (x + 4)(x-6)

<=> f(x) = x^{2} - 2x -24

We will convert to vertex form

<=> f(x) = (x^{2} - 2x +1) - 25

<=> f(x) = (x-1)^{2} -25

=> the vertex of the function is: (1,-25)

We choose: a. The vertex of the function is at (1,-25)

Let analyse other possible answers:

<u>c. The graph is increasing only on the interval -4< x < 6.</u>

Because the parameter a =1 so the graph open up all over its domain and the vertex is the lowest point.

So the graph is increasing in the domain (1, +∞)

=> C is wrong

<u>d. The graph is positive only on one interval, where x <-4</u>

Wrong, The graph is positive only on one interval, where x > 6

<u>e. The graph is negative on the entire interval</u>

Wrong, The graph is negative only on one interval, where -4< x < 6.

7 0
4 years ago
=
sergij07 [2.7K]

Answer:

I. L = 17 cm.

II. W = 11 cm.

Step-by-step explanation:

Let the length of the rectangle be L.

Let the width of the rectangle be W.

Given the following data;

Perimeter of rectangle = 56cm

Translating the word problem into an algebraic expression, we have;

L = W + 6 .....equation 1

The perimeter of a rectangle is given by the formula;

P = 2(L + W)

56 = 2(L + W) ......equation 2

Substituting eqn 1 into eqn 2, we have;

56 = 2(W + 6 + W)

56 = 2(6 + 2W)

Opening the bracket, we have;

56 = 12 + 4W

4W = 56 - 12

4W = 44

W = 44/4

W = 11 cm

Next, we would find the length of the rectangle;

From eqn 1;

L = W + 6

L = 11 + 6

L = 17 cm

7 0
3 years ago
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