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k0ka [10]
3 years ago
14

(2-4d)(2+4d)=0 Help please, Its the 0 property

Mathematics
1 answer:
lianna [129]3 years ago
4 0

Answer:

d1=-1/2,d2=1/2

Step-by-step explanation:

hope this helps

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Un tubo puede contener 35 l de agua por metro si mide 97 metros ¿Cuanto pesara el agua que contiene al es lleno
Mariana [72]

Respuesta:

3395 L

Explicación paso a paso:

Dado que el tubo contiene 35 L de agua por metro.

Esto significa que el volumen por metro del tubo es de 35 litros.

Longitud total del tubo = 97 metros

Volumen de agua en toda la longitud del tubo:

Volumen por metro * 97

35 L * 97

= 3395 litros

Por lo tanto, peso cuando está lleno = 3395 L

5 0
2 years ago
Compounds are different than elements because compounds are-
lutik1710 [3]

Step-by-step explanation:

A compound contains atoms of different elements chemically combined together in a fixed ratio. An element is a pure chemical substance made of same type of atom. ... Compounds contain different elements in a fixed ratio arranged in a defined manner through chemical bonds. They contain only one type of molecule.

4 0
3 years ago
Math help, please? <br> 20 points ! <br><br> Find the indicated limit, if it exists.
NNADVOKAT [17]

I think this the correct solution. but please correct me if I'm wrong

7 0
3 years ago
A kite is flying 20 ft off the ground. Its line is pulled taut and casts a 15 ft - shadow. Find the length of the line. If neces
Kryger [21]

Answer:

The answer to your question is 25 ft

Step-by-step explanation:

Data

height = 20 ft

leg = 15 ft

length of the line = ?

To solve this problem use the Pythagorean theorem.

Height = short leg = b

leg = long leg = a

length of the line = hypotenuse = c

- Substitution

         c² = (20)² + (15)²

-Simplification

         c² = 400 + 225

         c² = 625

-Result

         c = \sqrt{625}

         c = 25 ft

6 0
2 years ago
In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
snow_lady [41]

If ΔACB is an isosceles triangle, then ∠A ≅ ∠B and AC ≅ CB

Since ∠C = 120° and ∠A + ∠B + ∠C = 180°, then ∠A = 30° and ∠B = 30°

Next, look at ΔADB.  ∠A + ∠D + ∠B = 180°, so ∠A + 90° + 30° = 180° ⇒ ∠A = 30°

Now look at ΔADC.  Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC <em>per angle addition postulate.</em>

Now that we have shown that ΔADB and ΔADC are 30-60-90 triangles, we can use that formula to calculate the side lengths.

CD = 4 cm (given) so AC = 2(4 cm) = 8 cm

Since AC ≅ BC, then BC = 8 cm. Therefore, BD = 4 + 8 = 12 <em>by segment addition postulate.</em>

Lastly, look at ΔBHD.  Since ∠B = 30° and ∠H = 90°, then ∠D = 60°. So, ΔBHD is also a 30-60-90 triangle.

BD = 12 cm, so HD = \frac{12}{2}cm = 6 cm

Answer: 6 cm



8 0
3 years ago
Read 2 more answers
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