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3 years ago

8

Find the area of the irregular shape. Round to the nearest tenth.

1 answer:

svp [43]3 years ago

3 0

Given:
Irregular Shape:
Semi-circle and rectangle:

Area of a rectangle = l * w
Area of a semi-circle = (π r²)/2

Area of rectangle = 8 cm * 5 cm = 40cm²
Area of a semi-circle = (3.14 (4²))/2 = (3.14*16)/2 = 50.24/2 = 25.12cm²
4² is taken from diameter of 8cm divided by 2 to get the radius.

Total area = 40 cm² + 25.12 cm² = 65.12 cm²

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Which fraction is larger: 1/4 or 2/4

melisa1 [442]

No, the answer is 1/2 (2/4). If you have a pie, cut 4 pieces, and take one piece, that is 1/4. If you cut a pie in two pieces and take one piece, you took 1/2 AND that piece you took would be bigger than the 1/4 piece.

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3 years ago

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Which statement best reflects the solution(s) of the equation?

Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0$

Now, factoring the term:

$x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2$

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ the denominator becomes zero i.e

$\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}$

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2 in the equation,

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$

$\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2$

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

#learnwithBrainly

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3 years ago

-5/12 - (-9/3) what is the answer for this equation

WINSTONCH [101]

Answer:

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Step-by-step explanation:

Simple fraction problem

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1 year ago

Find f(x) if it is known that f(x+3)=4x+12.

MArishka [77]

Solution:

we are given that

$f(x+3)=4x+12$

we have been asked to find f(x).

we can find the value of f(x) by re-writing the given function in the form of f(x+3) and thereafter we will replace (x+3) by x.

we can re-write the given function as below

$f(x+3)=4(x+3)\\\\\Rightarrow f(x)=4x\\$

Hence the expression representing f(x) is f(x)=4x+3.

8 0

2 years ago

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zepelin [54]

Answer:

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Step-by-step explanation:

Add all the numbers

Divide by 9

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3 years ago