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melomori [17]
1 year ago
6

Help me please translations hw

Mathematics
2 answers:
RUDIKE [14]1 year ago
6 0

The locations of the vertices are shown below:

  1. (- 5, 4), (- 4, 4), (- 5, 2)
  2. (- 4, 1), (- 1, 2), (0, - 1), (- 2, - 5)
  3. (2, 5), (3, 4), (1, 2)
  4. (3, - 5), (- 2, - 3), (0, - 1)
<h3>What are the coordinates of the images resulting from a translation?</h3>

Herein we find four representations of polygons on Cartesian plane and we must determine the coordinates of the images generated by translation, a kind of rigid transformations. Translation is described by the following operation:

P'(x, y) = P(x, y) + T(x, y)

Where:

  • P(x, y) - Original point
  • P'(x, y) - Resulting point
  • T(x, y) - Translation vector

Case 1 (K(x, y) = (3, - 3), X(x, y) = (4, - 3), R(x, y) = (3, - 5), T(x, y) = (- 8, 7))

K'(x, y) = (3, - 3) + (- 8, 7) = (- 5, 4)

X'(x, y) = (4, - 3) + (- 8, 7) = (- 4, 4)

R'(x, y) = (3, - 5) + (- 8, 7) = (- 5, 2)

Case 2 (E(x, y) = (0, 2), X(x, y) = (3, 3), V(x, y) = (4, 0), Z(x, y) = (2, - 4), T(x, y) = (- 4, - 1))

E'(x, y) = (0, 2) + (- 4, - 1) = (- 4, 1)

X'(x, y) = (3, 3) + (- 4, - 1) = (- 1, 2)

V'(x, y) = (4, 0) + (- 4, - 1) = (0, - 1)

Z'(x, y) = (2, - 4) + (- 4, - 1) = (- 2, - 5)

Case 3 (G(x, y) = (- 4, 5), J(x, y) = (- 3, 4), U(x, y) = (- 5, 2), T(x, y) = (6, 0))

G'(x, y) = (- 4, 5) + (6, 0) = (2, 5)

J'(x, y) = (- 3, 4) + (6, 0) = (3, 4)

U'(x, y) = (- 5, 2) + (6, 0) = (1, 2)

Case 4 (V(x, y) = (0, 0), Y(x, y) = (- 5, 2), F(x, y) = (- 3, 4), T(x, y) = (3, - 5))

V'(x, y) = (0, 0) + (3, - 5) = (3, - 5)

Y'(x, y) = (- 5, 2) + (3, - 5) = (- 2, - 3)

F'(x, y) = (- 3, 4) + (3, - 5) = (0, - 1)

To learn more on rigid transformations: brainly.com/question/28004150

#SPJ1

hjlf1 year ago
3 0

Answer:

See attachments.

Step-by-step explanation:

A translation is a type of <u>transformation</u> that moves a figure left, right, up or down.  Every point on the original figure is translated (moved) by the same distance in the same direction.

  • If a figure is to be moved left, <u>subtract</u> the number of units it is to be moved from the x-values.
  • If a figure is to be moved right, <u>add</u> the number of units it is to be moved to the x-values.
  • If a figure is to be moved up, <u>add</u> the number of units it is to be moved to the y-values.
  • If a figure is to be moved down, <u>subtract</u> the number of units it is to be moved from the y-values.

<h3><u>Question 1</u></h3>

Coordinates of the given <u>pre-image</u>:

  • K = (3, -3)
  • R = (3, -5)
  • X = (4, -3)

Given <u>mapping rule</u>:

(x, y) \rightarrow (x-8, y+7)

This tells us to subtract 8 from the x-values and add 7 to the y-values.

\sf \implies K(3,-3) \rightarrow K'(3-8, -3+7)=K'(-5,4)

\sf \implies R(3,-5) \rightarrow R'(3-8, -5+7)=R'(-5,2)

\sf \implies X(4,-3) \rightarrow X'(4-8, -3+7)=X'(-4,4)

<h3><u>Question 2</u></h3>

Coordinates of the given <u>pre-image</u>:

  • E = (0, 1)
  • X = (3, 3)
  • V = (4, 0)
  • Z = (2, -4)

Given <u>mapping rule</u>:

(x, y) \rightarrow (x-4, y-1)

This tells us to subtract 4 from the x-values and subtract 1 from the y-values.

\sf \implies E(0,1) \rightarrow E'(0-4, 1-1)=E'(-4,0)

\sf \implies X(3,3) \rightarrow X'(3-4, 3-1)=X'(-1,2)

\sf \implies V(4,0) \rightarrow V'(4-4, 0-1)=V'(0,-1)

\sf \implies Z(2,-4) \rightarrow Z'(2-4, -4-1)=Z'(-2,-5)

<h3><u>Question 3</u></h3>

Coordinates of the given <u>pre-image</u>:

  • G = (-4, 5)
  • J = (-3, 4)
  • U = (-5, 2)

Given <u>mapping rule</u>:

(x, y) \rightarrow (x+6, y)

This tells us to add 6 to the x-values and the y-values remain unchanged.

\sf \implies G(-4,5) \rightarrow G'(-4+6, 5)=G'(2,5)

\sf \implies J(-3,4) \rightarrow J'(-3+6, 4)=J'(3,4)

\sf \implies U(-5,2) \rightarrow U'(-5+6, 2)=U'(1,2)

<h3><u>Question 4</u></h3>

Coordinates of the given <u>pre-image</u>:

  • F = (-3, 4)
  • V = (0, 0)
  • Y = (-5, 2)

Given <u>mapping rule</u>:

(x, y) \rightarrow (x+3, y-5)

This tells us to add 3 to the x-values and subtract 5 from the y-values.

\sf \implies F(-3,4) \rightarrow F'( -3+3, 4-5)=F'(0,-1)

\sf \implies V(0,0) \rightarrow V'( 0+3, 0-5)=V'(3,-5)

\sf \implies Y(-5,2) \rightarrow Y'( -5+3, 2-5)=Y'(-2,-3)

Learn more about transformations here:

brainly.com/question/28354239

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19. Describe the sequence of transformations from quadrilateral WXYZ to W"X"Y"Z"
Tpy6a [65]

Answer:

The sequence is as following:

1. Reflection 180°

2. Reflection over the line x=5  

3. Translation 2 units down.

Step-by-step explanation:

The question is as following:

Describe the sequence of transformations from Quadrilateral WXYZ to W”X”Y”Z”.

The picture is a coordinate plane with

W= (-8,8)

X= (-2,8)

Y= (-2,4)

Z= (-8,4)

W”= (2,-10)

X”= (8,-10)

Y”= (8,-6)

Z”= (2,-6)

=================================

See the attached figure

The sequence is:

Reflection 180° ⇒ Reflection over the line x=5 ⇒ translation 2 units down.

Rule of reflection 180° is (x, y) → (–x, –y)

Rule of reflection over the line x=5 is (x, y) → (–x+10 , y)

Rule of translation 2 units down is (x, y) → (x , y–2)

The way of thinking:

1. The rectangle at the second quadrant, we need make it at the fourth quadrant, so, the suitable is <u>Reflection 180°</u>

2. After reflection 180°, it is noticed that we need reverse the vertices so we need to make a reflection over its vertical axis which is at <u>x = 5</u>

3. We need to translate it 2 units down to overlap with the required coordinates.

<u>Check the points:</u>

W(-8,8) ⇒ (8,-8) ⇒ (2,-8) ⇒ (2,-10)⇒W"

X(-2,8) ⇒ (2,-8) ⇒ (8,-8) ⇒ (8,-10)⇒X"

Y(-2,4) ⇒ (2,-4) ⇒ (8,-4) ⇒ (8,-6)⇒Y"

Z(-8,4) ⇒ (8,-4) ⇒ (2,-4) ⇒ (2,-6)⇒Z"

5 0
2 years ago
a ramp measures 6 feet long. if the ramp is 12 inches tall, what is the horizontal distance it covers? i'll give brainliest to w
luda_lava [24]

we know that

1 ft--------> is equals to 12 in

the ramp is 12 inches tall----------> 1 ft tall

A ramp measures------------------>  6 ft long

applying the Pythagorean theorem

c²=a²+b²

where

c-----> 6 ft long

a----> horizontal distance

b-----> 1 ft tall

a²=c²-b²------> a²=6²-1²-----> a²=35------> a=√35------> a=5.92 ft

the answer is

5.92 ft

6 0
2 years ago
Read 2 more answers
The cube has a volume of 27 in3. Find the volume of a scaled image with a scale factor of 2. in3 Cube with a side length of thre
WINSTONCH [101]
The new size of cube's side is 6. V new cube = 6*6*6 = 216 

7 0
3 years ago
Please explain your answer. Thank you!!
Ad libitum [116K]

Answer:

(A) 180

Step-by-step explanation:

We have to treat those player selections as independent events, since one doesn't influence the other (the fact you chose Joe as a guard, shouldn't have an influence on who'll pick as center, unless there's bad blood between some players... but that's a whole other story).

So, how many ways to pick 2 guards from a selection of 4?  The order doesn't seem to matter here, since they don't specify for example that Joe can only play on the left side).  So, it's a pure combination calculation:

C(4,2) = \frac{4!}{2! * (4 - 2)!} = \frac{24}{2 * 2} = 6

C(4,2) = 6.

How many ways to pick the 2 forwards from a group of 5?  Using the same calculation, we get:

C(5,2) = 10.

And of course, the coach has 3 ways to pick a center player from 3.

Then we multiply the possible ways to pick guards, forwards and center...

6 * 10 * 3 = 180 ways.

7 0
3 years ago
Is it A- translation B- rotation C- Reflection D- Dilation?
Oliga [24]

Answer:

rotation

Step-by-step explanation:

7 0
3 years ago
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