Answer:
<h2>x = 28</h2><h2>CE = 132</h2><h2 />
Step-by-step explanation:
|<------------- CE -------------------->|
C-------------------D-------------------E
2x + 10 3x - 18
2x + 10 = 3x - 18
2x - 3x = -18 - 10
-x = -28
x = 28
CE = 2x + 10 + 3x - 18
CE = 2(28) + 10 + 3(28) - 18
CE = 56 + 10 + 84 - 18
CE = 132
Yep the other one is right it is (4,-2)
1q+2=-6q+3+8q+4
1q+2=2q+7
<span>-2q -2q
</span>-q+2=7
<span> -2 -2
</span>-q=<span>5
-1 -1
q=-5
</span>
Input (x-value)
Output (y-value)
You need to find the x-value that produces a y-value of -1. Since you know:
y = -1 Use the rule, and substitute/plug this into the equation
y = -2x + 33 Plug in -1 for "y" in the equation since y = -1
-1 = -2x + 33 Subtract 33 on both sides
-1 - 33 = -2x + 33 - 33
-34 = -2x Divide -2 on both sides to get "x" by itself

17 = x
An input of 17 yields an output of -1