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Y_Kistochka [10]
2 years ago
13

Help me please i need help im terable at math

Mathematics
2 answers:
natita [175]2 years ago
3 0

Answer:

83

Step-by-step explanation:

70=x-13

70+13=x-13+13

83=x

Margarita [4]2 years ago
3 0
The answer is 83 just make sure you show you work, as long you have 83 it will be right
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F two angles form a linear pair, then they are adjacent and
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A linear pair is two angles that are adjacent and whose non-common sides form a straight line. If two angles are a linear pair, then they are supplementary. 
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How do I express y in terms of x?
Dmitrij [34]

Answer:

Solve for ‘y' means, solve the equation to get the value of y.

And in terms of x , means, value of y not necessarily in pure constant form, but in the form of x.

Step-by-step explanation: Here's an example

3y +x = 7

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5 0
3 years ago
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8 0
3 years ago
Students of Grade 5 together sold T- shirts for a 6 fundraiser at $ 360. Find the average number of T- shirts each student sold
vekshin1

Answer:

$60

Step-by-step explanation:

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note: I feel like this question has a wierd wording

5 0
2 years ago
Read 2 more answers
A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =
tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

f(x)=-16x^2+64x+5

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

10=-16x^2+64x+5

Subtracting 10 from both sides:

-16x^2+64x-5=0

For simplicity, divide both sides by -1:

16x^2-64x+5=0

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Substitute:

\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}

Evaluate:

\displaystyle x=\frac{64\pm\sqrt{3776}}{32}

Simplify the square root:

\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}

Therefore:

\displaystyle x=\frac{64\pm8\sqrt{59}}{32}

Simplify:

\displaystyle x=\frac{8\pm\sqrt{59}}{4}

Approximate:

\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0
2 years ago
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