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1 year ago

I need help with this question

Mathematics

1 answer:

Pepsi [2]1 year ago

4 0

We can isolate y in the linear equation to get:

y = 4x - 8

<h3>How to isolate the variable?</h3>

Here we have the linear equation:

8x - 2y = 16

Now, remember that we can perform the same operation in both sides of the equation, and the equation don't changes.

To isolate y, we can start by subtracting 8x in both sides, so we get:

-2y = 16 - 8x

Now we should divide both sides by -2:

y = (16 - 8x)/(-2) = -8 + 4x

y = 4x - 8

If you want to learn more about linear equations:

brainly.com/question/1884491

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Olenka [21]

Answer:

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2 is a reflection

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Step-by-step explanation:

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2 years ago

Haben knows that the angle of elevation from the top of a rock formation to a stake in the ground 50 feet from its base is 42°.

Murrr4er [49]

Answer:

The height of the rock formation is $45.02\ ft$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

$tan(42\°)=h/50$

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3 years ago

Read 2 more answers

Evaluate 5c+cd when c=1/5 and d=15

oee [108]

5*1/5+1/5*15=4
1 + 3 =4

This should equal 4 if I did this correctly.

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3 years ago

A colony of bacteria is grown under ideal conditions in a laboratory so that the population increases exponentially with time. A

Naddik [55]

Answer:

Initial bacterias = 6006000

Altought I believe is safe to assume that the values were 192,000 and 384,000 instead of 192,192,000 and 384,384,000, in that case the initial bacterias is 6000

Step-by-step explanation:

A exponential growth follows this formula:

Bacterias = C*rⁿ

C the initial amount

r the growth rate

n the number of time intervals

Bacterias (55 hours) = 192,192,000

Bacterias (66 hours) = 384,384,000

$Bacterias(55hours)=C*r^{{\frac{55-t}{t}}} \\Bacterias (66hours) = C*r^{\frac{66-t}{t}}}$

If you divide both you can get the growth rate:

$\frac{Bacterias (66hours)}{Bacterias(55hours)}=\frac{C*r^{\frac{66-t}{t}}}{C*r^{{\frac{55-t}{t}}}} \\\frac{384,384,000}{192,192,000} =r^{\frac{66-t}{t} -\frac{55-t}{t} } \\2 =r^{\frac{11}{t}}$

So with that r = 2 and each time interval correspond to 11 years

Then replacing in one you can get the initial amount of C

$Bacterias (55hours)=C*2^{\frac{55-11}{11} } 192,192,000 = C*32\\C= 6006000$

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2 years ago

Whoever answers this gets brainliest plsss help

Karolina [17]

hope it helped. I have solved in the same paper. plz don't mind.

7 0

2 years ago