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Serhud [2]
1 year ago
13

F(x) = 6x − x2, f(6 + h) − f(6) h , h ≠ 0

Mathematics
1 answer:
emmasim [6.3K]1 year ago
8 0

The value of f(6 + h) − f(6)  is 36 + 6h - g^2 - 2gh - h^2.

Given,

f(x) = 6x − x2

We need to find f(6 + h) − f(6)

We have,

f(x) = 6x − x2

Find f(6 + h)

f(x) = 6x - x^2

Putting x = 6 + h

f(6+h)

= 6(6+h) - (g+h)^2

= 36 + 6h - (g^2 + 2gh + h^2)

= 36 + 6h - g^2 - 2gh - h^2 ________(A)

Find f(6)

f(x) = 6x - x^2

f(6)

= 6(6) - 6^2

= 36 - 36

= 0  ________(B)

Find f(6 + h) − f(6)

From A and B

= 36 + 6h - g^2 - 2gh - h^2 - 0

= 36 + 6h - g^2 - 2gh - h^2

Thus the value of f(6 + h) − f(6) is 36 + 6h - g^2 - 2gh - h^2.

Learn more about evaluating function here:

brainly.com/question/11270390

#SPJ1

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