Answer:
a. The probability that a customer purchase none of these items is 0.49
b. The probability that a customer purchase exactly 1 of these items would be of 0.28
Step-by-step explanation:
a. In order to calculate the probability that a customer purchase none of these items we would have to make the following:
let A represents suit
B represents shirt
C represents tie
P(A) = 0.22
P(B) = 0.30
P(C) = 0.28
P(A∩B) = 0.11
P(C∩B) = 0.10
P(A∩C) = 0.14
P(A∩B∩C) = 0.06
Therefore, the probability that a customer purchase none of these items we would have to calculate the following:
1 - P(A∪B∪C)
P(A∪B∪C) =P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C)
= 0.22+0.28+0.30-0.11-0.10-0.14+0.06
= 0.51
Hence, 1 - P(A∪B∪C) = 1-0.51 = 0.49
The probability that a customer purchase none of these items is 0.49
b.To calculate the probability that a customer purchase exactly 1 of these items we would have to make the following calculation:
= P(A∪B∪C) - ( P(A∩B) +P(C∩B) +P(A∩C) - 2 P(A ∩ B ∩ C))
=0.51 -0.23 = 0.28
The probability that a customer purchase exactly 1 of these items would be of 0.28
Answer:
MQ=14
Step-by-step explanation:
The two triangles are similar
So the equation is
12/72=x/12
1/6=x/12
x=2
D + q = 110......d = 110 - q
0.10d + 0.25q = 20.30
0.10(110 - q) + 0.25q = 20.30
11 - 0.10q + 0.25q = 20.30
-0.10q + 0.25q = 20.30 - 11
0.15q = 9.30
q = 9.30/0.15
q = 62 <==== there are 62 quarters
d = 110 - q
d = 110 - 62
d = 48 <==== there are 48 dimes
9 out of 12 = 9/12 which can be simplified to 3/4. So the team wins 3/4 of its games. 3/4 of 64 = 64 divided by 4 = 16. 16 x 3 = 48.
Answer:
The answer is 3030.72 m³
Step-by-step explanation:
Please refer to attached file for graphical representation.
Formulas used:
Area = (a*b)/2
Trigonometry: Tan (t) = opposite/adjacent
Assume:
Villager plot has 3 sides: hypotenuse=C, adjacent=A, opposite=B
Plot given has 3 sides: hypotenuse=z, adjacent=y, opposite=x
Angle common between them is t.
<u>Step 1</u>:
For t:
Tan (t) = a/b
Tan (t) = 123/50
Tan (t) = 2.46
<u>Step 2:</u>
For y:
Tan (t) = y/x
2.46 = y/6
y = 2.46*6
y = 14.76
<u>Step 3:</u>
Villagers old plot area: B = (a*b)/2 = (123*50)/2
B = 3075 m³
<u>Step 4:</u>
Plot donated area: C = (x*y)/2 = (6*14.76)/2
C = 44.28 m³
<u>Step 5:</u>
Villager remaining plot:
A = B-C
A= 3075-44.28
A = 3030.72 m³
