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Sergeu [11.5K]
3 years ago
9

Una estudiante gráfica muestras de mayolicas que desea comprar su papa para poner en el piso de la ducha. Las representaciones g

ráficas de 3/4 corresponde a la parte coloreada en cada una de las mayolicas ¿Son equivalentes las fracciones que representan la parte coloreada de cada muestra? ¿Cómo verifico que 2 fracciones son equivale?
Mathematics
1 answer:
Arisa [49]3 years ago
6 0
So company so yam soy
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What is -4.5= a - 8
murzikaleks [220]

Answer:

Step-by-step explanation: -4.5=a-8

1. add 8 to both sides -4.5+8= 3.5

2. since you added 8 to negative 8 you get zero so it just goes away

3. ANSWER= 3.5=a

7 0
3 years ago
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you want to put 520 quarters in coin wrappers. you need one wrapper for every $10 in quarters. write an equation you can use to
Lisa [10]
40c=520
This is the proper equation because there are 40 quarters in $10. Thus, if we could only fit $10 worth of quarters in each wrapper, we can only fit 40quarters in each wrapper. C represents the amount of wrappers we will need.

Hope this helps!
6 0
3 years ago
Please help due soon I don’t get it
natka813 [3]

Answer:

x>0 and y>0

Step-by-step explanation:

1= ++ 2= -+ 3= -- 4= +-

6 0
2 years ago
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EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att
aliina [53]
y=x(x-2)^2
\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0
\implies x=\dfrac23,x=2

are the critical points, and judging by the picture alone, you must have b=\dfrac23 and a=2. (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of \dfrac{\mathrm dy}{\mathrm dx}=y', which entails first finding the second derivative:

y'=3x^2-8x+4
\implies y''=6x-8

setting equal to 0 and finding the critical point:

6x-8=0\implies x=\dfrac86=\dfrac43

This is to say the minimum value of \dfrac{\mathrm dy}{\mathrm dx} *occurs when x=\dfrac43*, but this is not necessarily the same as saying that \dfrac43 is the actual minimum value.

The minimum value of \dfrac{\mathrm dy}{\mathrm dx} is obtained by evaluating the derivative at this critical point:

m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43
4 0
3 years ago
A child walks 5.0 meters north, then 4.0 meters east, and finally 2.0 meters south. What is the magnitude of the resultant displ
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<h2>file:///E:/Kinematics%20Review%208080.pdf</h2><h2></h2><h2>here is your answer</h2>
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