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Radda [10]
1 year ago
12

What two nonnegative real numbers with a sum of 64 have the largest possible product?

Mathematics
1 answer:
Otrada [13]1 year ago
6 0

The two non negative real numbers with a sum of 64 that have the largest possible​ product are; 32 and 32.

<h3>How do we solve the nonnegative real numbers?</h3>

Let the two numbers be x and y.

Thus, if their sum is 64, then we have;

x + y = 64

y = 64 - x

Their product will be;

P = xy

Putting (64 - x) for y in the product equation we have;

P = (64 - x)x

P = 64x - x²

Since the product is maximum, let us find the derivative;

P'(x) = 64 - 2x

At P'(x) = 0, we have;

64 - 2x = 0

2x = 64

x = 64/2

x = 32

Thus; y = 64 - 32

y = 32

Read more about nonnegative real numbers

brainly.com/question/9580755

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Answer:

\sf 6. \quad \dfrac{7}{10}

\sf 7. \quad \dfrac{5}{17}

Step-by-step explanation:

<h3><u>Question 6</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

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42 and 60 share one 2 and one 3 in common.

Multiply them together to get the GCF:  2 × 3 = 6.

Therefore, 6 is the GCF of 42 and 60.

Divide the numerator and the denominator by the found GCF:

\implies \sf \dfrac{42 \div 6}{60 \div 6}=\dfrac{7}{10}

<h3><u>Question 7</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

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  • 272 = 2 × 2 × 2 × 2 × 17

80 and 272 share four 2s in common.

Multiply them together to get the GCF:  2 × 2 × 2 × 2 = 16.

Therefore, 16 is the GCF of 80 and 272.

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\implies \sf \dfrac{80 \div 16}{272 \div 16}=\dfrac{5}{17}

5 0
1 year ago
Read 2 more answers
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