Answer:
0.7455
Step-by-step explanation:
First, we note that there are C
= 220 ways of selecting the defective items.
The probability that the inspector will have to test at least 9 widgets would be 1 minus the probability that the inspector will have to test 8 or less widgets.
This is 1 - P(8 or less widgets have to be checked)
1 - 
= 1 - 56/220
= 1 - 0.2545
= 0.7455
First you need to find the r, if C=2pieR, than 2.4=2pieR now you divide 2.4 by 2 so you got 1.2=pieR now you divide 1.2 by pie and obtained aproximately 0.38 miles, that is your R, now you do pie multiply by 0.38 exposant 2 and there you go, your answer is aproximately 0.45 miles2 :)
Answer:


Step-by-step explanation:
<u>Equation Solving</u>
We are given the equation:
![\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D)
i)
To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.
We have to make it in steps like follows.
Cube both sides:
![\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E3%3D%5Cleft%28%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D%5Cright%29%5E3)
Simplify the radical with the cube:

Multiply by 2y+9

Simplify:

Operate the parentheses:


Subtract 3y and
:

Factor y out of the left side:

Divide by
:

ii) To find y when x=2, substitute:





All work<span> should be submitted in its original form. ... (b) </span>If<span> v=— </span>show<span> that z=a^~^\ and </span>find<span> from either equation 1 ' " x-a' p—a' H the </span>value<span> of a in order that </span>x<span>='i when y=2. Also, for this ... Thence </span>find<span> the length of an edge of such a box weighing </span>18<span>$ pounds, </span>if<span> the thickness is 1 inch and the weight 1 ounce to the cubic inch.</span>