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Alex787 [66]
4 years ago
5

Can someone check these answers for me

Mathematics
1 answer:
Salsk061 [2.6K]4 years ago
5 0
Hun, these questions look opinionated. They are asking what all you can do and what you need help with.
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Is income take home pay?​
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Answer:

Take-home pay is the net amount of income received after the deduction of taxes, benefits, and voluntary contributions from a paycheck.

Step-by-step explanation:

Hope this helps!

3 0
3 years ago
What shape will you get if you put 3 diamonds together
8_murik_8 [283]

I think just a trapezoid no others

Hope I helped, Good luck

 = )

4 0
3 years ago
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Which pair of angles are alternate interior angles?
Paraphin [41]

we know that

<u>Alternate interior angles</u> are two interior angles which lie on different parallel lines and on opposite sides of a transversal. Alternate interior angles are congruent

see the attached figure with letters to better understand the problem

in this problem

the parallel lines are the lines a and b

the transversal line is the line c

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the alternate interior angles are the Angle 3 and Angle 6

m∠3=m∠6

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<u>the answer is the option</u>

Angle 3 and Angle 6

6 0
3 years ago
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Write three equivalent expressions for the expression 16x+64  
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1. 8x + 32
2. 4x + 16
3. 2x + 8
7 0
4 years ago
According to a survey by the Administrative Management Society, one-half of U.S. companies give employees 4 weeks of vacation af
andreyandreev [35.5K]

Answer:

a

P(2\leq X\leq 5)=0.875

b

P(X

Step-by-step explanation:

Let the random X variable representing the 6 companies that give 4 weeks of vacation after 15 years of employment:

-let p=0.5 be the probability of vacation. Since the companies are independent, X assumes a binomial random variable:P(X=x)=b(x;6,0.5)\\\\={6 \choose x}(0.5)^x(0.5)^{6-x}\\\\={6 \choose x}(0.5)^6, \ x=0,1,2,3...\ \ \ eqtn1

#Probability that the number of companies that give vacation is anywhere from 2 to 5:

We use equation 1;

P(2\leq X\leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\={6 \choose 2}(0.5)^6+{6 \choose 3}(0.5)^6{6 \choose 4}(0.5)^6+{6 \choose 5}(0.5)^6\\\\=0.0156(15+20+15+6)\\\\=0.875

Hence the probability that between 2 and 5 companies give vacation is 0.875

b. The probability that fewer than 3 companies give vacation is calculated as:

From equation one we get:

P(X

Hence the probability that less than three companies give vacation is 0.3432

3 0
3 years ago
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