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4 years ago

Whats 2+2 :O this is for y'all to get points your welcome <3

Mathematics

1 answer:

Harman [31]4 years ago

7 0

Answer:

Step-by-step explanation:

Thank you so much lol :3

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Need help!! I can't figure this out

Sidana [21]

9514 1404 393

Answer:

12. $1,035,057.23

13. $988,881.23

14. $7,762.93

15. $8,686.16

16. $967,647.66

Step-by-step explanation:

The annuity and amortization formulas are used for problems like this.

sum of monthly payments = P((1 +r/12)^(12t) -1)/(r/12)

monthly amount available = P(r/12)/(1 -(1 +r/12)^(-12t))

12. The sum of monthly payments of 74, accumulated at 9% compounded monthly for 52 years is ...

A = ($74)((1 +.09/12)^(12·52) -1)/(.09/12) = $1,035,057.23

13. The total of payments is ...

$74×12×52 = $46,176

So, the interest earned is ...

$1,035,057.23 -46,176 = $988,881.23

14. The amount available in perpetuity is the monthly interest on this account balance.

$1,035,057.23 × .09/12 = $7,762.93

15. The monthly amount available for 25 years is found from the amortization formula:

A = $1,035,057.23(.09/12)/(1 -(1 +.09/12)^(-12·25)) = $8686.16

16. The amortization formula is used for this, too.

8066 = P(.094/12)/(1 -(1 +.094/12)^(-12·30)) = 0.00833568P

P = $8066/0.00833568 = $967,647.66

7 0

3 years ago

How much of a radioactive kind of thorium will be left after 14,680 years if you start with

babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

$N(t)= N_{0}e^{-kt}$

N(t) = amount after the time <em>t</em>

$N_{0}$ = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

$N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t}$ or more simply $N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }$

$t_{h}$ = time of the half-life

We know that $N_{0}$ = 35,912, t = 14,680, and $t_{h}$ =7,340

Plug these into the equation:

$N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }$

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0

2 years ago

What are the zeros of x^3 - 18x^2 +107x -210

trapecia [35]

Answer:

(−7)(−6)(−5) so the zeros are 5, 6, &7

Step-by-step explanation:

4 0

3 years ago

Three sixth-grade students competed in the 100-meter dash. The table shows their times.

Sergeeva-Olga [200]

Answer:

It is 12.9, 13.1, 13.2 C.

Step-by-step explanation:

5 0

3 years ago

Can someone please help me it's worth five points

Brilliant_brown [7]

The formula of a volume of a cone:

$V=\dfrac{1}{3}Bh=\dfrac{1}{3}\pi r^2h$

We have:

$r=12cm,\ h=8cm$

Substitute:

$V=\dfrac{1}{3}\pi\cdot12^2\cdot8=\dfrac{1}{3}\pi\cdot144\cdot8=\pi\cdot48\cdot8=384\pi\ cm^2\approx384\cdot3.14=1205.76\ cm^3\approx1206\ cm^3$

Answer: 1206 cm³

7 0

3 years ago