Question

What is an equation of the line that passes through the point (-5,3)(−5,3) and is parallel to the line 3x-5y=303x−5y=30?

Answer 1

The equation of the line which passes through the point (-5, 3) and is parallel to the equation 3x -5y = 30 is; 3x -5y = 30.

What is the equation of the line?

Since the line is parallel to the given line; 3x -5y = 30 whose slope is; 3/5.

Hence, since the two lines have equal slopes;

3/5 = (y-3)/(x-(-5))

3/5 = (y-3)/(x+5)

5y -15 = 3x +15

3x -5y = 30

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