The graph can be divided into two shapes. A rectangle and a right triangle.
The distance that the rover will cover if it completes one circuit can be computed using the Pythagorean theorem and adding the sides of the rectangle.
Rectangle:
Width = 4 - 2 = 2 meters
Length = 11 - 2 = 9 meters
Triangle = 16 - 2 = 14 ; 14 - 2 = 12 meters (this is the short leg)
long leg of the triangle = length of the rectangle = 9 meters.
12² + 9² = c²
144 + 81 = c²
225 = c²
√225 = √c²
15 = c
Point A to B = 4 - 2 = 2 meters
Point B to C = 15 meters
Point C to D = 16 - 2 = 14 meters
Point D to A = 11 - 2 = 9 meters
Total distance traveled = 2 + 15 + 14 + 9 = 40 meters.
Im going with C
hope this helps
So if we’re talking about meters per second, you would need to divide.
-17.5/5 = -3.5
NOW YOU THINK THATS YOUR ANSWER BUT NOO. You CANNOT have a negative second. So you take the absolute value of -3.5 and your answer would be 3.5
The rate of the anchor is 3.5 meters per second.
Answer:
The length of each side is 26.3 cm
Step-by-step explanation:
Opposite sides of an isoceles triangle are equal
The isoceles triangle is divided into 2 right-angled triangles so the length of one side can be calculated using trigonometric ratio
When the isoceles triangle is divided, the angle in the right-angled triangle is 20° (1/2 of 40°) and the base is 9cm (1/2 of 18 cm), the hypotenuse side is calculated using trigonometric ratio
Let the length of the hypotenuse side be y
9/y = sin 20°
y = 9/0.3420 = 26.3
Length of each side is 26.3 cm
Answer:
Step-by-step explanation:
Volume of the box = x³ +11x² + 20x – 32 I think the ' is a typo for ³
the width is x-1 and the height is x+8
Find an expression for the length
Vol = LWH solve L
Vol / (WH) = L so
L = (x³ +11x² + 20x – 32) / (x-1) (x+8)
so it would help to factor the numerator
(x³ +11x² + 20x – 32) I'm willing to bet (x-1) and (x+8) are factors
but I will plot the equation to find the three roots
(x³ +11x² + 20x – 32) = (x-1) (x+8) (x+4)
L = (x³ +11x² + 20x – 32) / (x-1) (x+8)
= (x-1) (x+8) (x+4) / (x-1) (x+8) the (x-1) and (x+8) cancel out leaving
L = (x + 4)
