Answer: the length of the field is 70 yards. The width of the field is 35 yards
Step-by-step explanation:
Let L represent the length of the rectangular athletic field.
Let W represent the width of the rectangular athletic field.
A rectangular athletic field is twice as long as it is wide. This means that
L = 2W
The formula for determining the perimeter of a rectangle is expressed as
Perimeter = 2(L + W)
If the perimeter of the athletic field is 210 yards, it means that
210 = 2(L + W)
L + W = 210/2 = 105
Substituting L = 2W into L + W = 105, it becomes
2W + W = 105
3W = 105
W = 105/3 = 35
L = 2W = 2 × 35
L = 70
Well if you tell me the distance of abcd from the speaker I could help u
bearing in mind B is at (4,3) and D is at (-2,-4).
Answer:
f(-2) = 20
Step-by-step explanation:
f(x) = 2x² - 3x + 6
f(-2) = 2(-2)² - 3(-2) + 6
= 2(4) + 6 + 6
= 8 + 12
= 20
