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leonid [27]
3 years ago
6

Plzzzz guys help :( Which of the following is the mid point of the line segment with endpoints -3 and 2 (a)5/2 (b) 1 (c) -1/2 (d

) -1 (e)-5/2
Mathematics
2 answers:
Monica [59]3 years ago
4 0

Answer:

<u>C</u> -1/2

Step-by-step explanation:

midpoint = sum of end points divide by 2.

here, midpoint = (-3+2)/2

=(-1/2)

Pavlova-9 [17]3 years ago
4 0

Answer:

- 1 / 2

Step-by-step explanation:

→ Add the 2 numbers together

-3 + 2 = -1

→ Divide answer by 2

- 1 ÷ 2 = - 1 / 2 or - 0.5

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Well 2,000 pounds is one ton. so it would be 3 tons and 1/2
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Paul filled pint containers with 440 cups of water. How many pint containers did Paul need? 1 pint = 2 cups
Tju [1.3M]
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You want to obtain a sample to estimate a population proportion. Based on previous evidence, you believe the population proporti
Ksenya-84 [330]

Answer:

We need a sample size of at least 369.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

\pi = 0.32

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large of a sample size is required?

We need a sample size of at least n.

n is found when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.645\sqrt{\frac{0.32*0.68}{n}}

0.04\sqrt{n} = 1.645\sqrt{0.32*0.68}

\sqrt{n} = \frac{1.645\sqrt{0.32*0.68}}{0.04}

(\sqrt{n})^{2} = (\frac{1.645\sqrt{0.32*0.68}}{0.04})^{2}

n = 368.02

Rounding up

We need a sample size of at least 369.

5 0
4 years ago
Principal:$500<br> Interest earned:$60<br> Time:3 years
Oksanka [162]
I = PRT 

I = (500)(60)(3)

I = 90000
7 0
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seraphim [82]
I am pretty sure D. Cause I did the problem and it seems to make sense
8 0
3 years ago
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