Well 2,000 pounds is one ton. so it would be 3 tons and 1/2
For this case we can make the following rule of three:
1pint ------> 2cups
x -----------> 440 cups
Clearing x we have:
x = (440/2) * (1)
x = 220 pint containers.
Answer:
Paul needs about:
x = 220 pint containers.
Answer:
We need a sample size of at least 369.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

For this problem, we have that:

90% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
How large of a sample size is required?
We need a sample size of at least n.
n is found when
. So






Rounding up
We need a sample size of at least 369.
I = PRT
I = (500)(60)(3)
I = 90000
I am pretty sure D. Cause I did the problem and it seems to make sense