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Eddi Din [679]
1 year ago
7

Roberto invested a total of $10,000, part at 6% and part at 9%. How much did he invest in the LOWER interest account if the tota

l interest earned in one year was $810?
Mathematics
1 answer:
Fofino [41]1 year ago
6 0

The amount invested in the lower interest account of 6% is $3,000

What is the interest on each account?

The interest on each account can be determined as the amount invested in the account multiplied by the interest rate earned by the account

Amount invested in the lower interest is X(assumed), as a result, the interest earned on the lower interest rate account is X multiplied by 6%

interest on lower interest account=0.06X

The balance remaining after having invested X in lower interest account is $10,000-X

interest on higher interest account=9%*($10,000-X)

interest on higher interest account=900-0.09X

total interest=0.06X+900-0.09X

total interest=$810

810=0.06X+900-0.09X

810=900-0.03X

0.03X=900-810

0.03X=90

X=90/0.03

X= LOWER interest account amount=$3,000

Find about more about investment combination on:brainly.com/question/17448028

#SPJ1

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