4x + 2y = 8 (1)
8x + 4y = -4y (2)
A) Two lines are parallel if they have the same gradient
- putting both equations into the gradient- intercept form ( y = mx + c where m is the gradient)
(1) 4x + 2y = 8
2y = 8 - 4x
y = -2x + 4
(2) 8x + 4y = -4y
<span> </span>8x = -4y - 4y
y =

y = -x
<span>
Thus the gradient of the two equations are different and as such the two lines are not parallel</span>
B) When two lines are perpendicular, the product of their gradient is -1

p = (-2) * (-1)
p = 2
<span> ∴
the two lines are not perpendicular either.</span>
Thus these lines are SKEWED LINES
Step-by-step explanation: |x − y| = 1, ok lets play as Alice, my number is y, and the bob number is x.
the condition says that x-y = 1 or x-y = -1.
so, if you know x, then y = 1 +y or y = y - 1. so you have two possibilities.
let's see two cases : first, let's suppose there are no code in the conversation. Then the only way of being shure of your number, is if one of them have the lowest positive number, so the other should have the next one. So if Bob have the number one, Alice knows for shure that she has the 2. Bob knows that she has a 2, but that means he could have a 1 or a 3, but when he sees that Alice is shure about her number, he knows that his number is the 1.
the second case is where the conversation may be a sort of code, saying a phrase x times and changing when x = the number of the other person, in this case, bob will have the 201 and alice the 202.
1047.84ft² is not covered by the pool.
Find the area of the yard covered by pull using the area of a circle formula (the height is irrelevant in this case). If the diameter of the pool is 24 feet, its radius is 12 (half of the diameter)
A = 3.14r^2
A =3.14(144)
A = 452.16 ft²
Subtract the area of the pool from the area of the yard to get the area of the yard that is not covered by the pool. If the dimensions of the yard are 30ft by 50ft, you multiply them to get the area: 1500ft²
Total yard area: 1,500ft²
Area of yard without pool: 1,500ft² - 452.16ft² = 1047.84ft²
The division ➗ ÷ sign will make the expression correct if you correct the question!
X³ = 125/27
Cube root both sides to isolate the variable:
∛x³ = ∛(125/27)
x = ∛(125/27)
∛125 = 5, ∛27 = 3
x = 5/3