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wolverine [178]
2 years ago
11

suppose that two hydroxides, moh and m′ (oh)2, both have a ksp of 1.39 × 10−12 and that initially both cations are present in a

solution at concentrations of 0.001 mol/l. at what ph will the hydroxide precipitate when solid naoh is added to the solution?
Chemistry
1 answer:
11Alexandr11 [23.1K]2 years ago
8 0

When base is added in order to increase the pH of a solution, it results in MOH salt <u>precipitating first.</u>

Equation :

MOH (s)  ⇄ M⁺ (aq)  ₊ OH⁻(aq)

Ksp = [M⁺] [OH⁻]

Ksp = 1.39×10⁻¹² and [M⁺] = 0.001M

∴ 1.39×10⁻¹² = (0.001M) [OH⁻]

[OH⁻] =  1.004×10⁻¹⁹M

pOH = -log [OH⁻] =  11.9

pH = 14 - pOH

= 14 - 11.9

<u>pH = 2.1</u>

To learn more about solubility equilibrium ;

https://brainly.in/question/9213521

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