This problem is incomplete. Luckily, I found a similar problem from another website shown in the attached picture. The data given can be made to use through the Clausius-Clapeyron equation:
ln(P₂/P₁) = (-ΔHvap/R)(1/T₂ - 1/T₁)
where
P₁ = 14 Torr * 101325 Pa/760 torr = 1866.51 Pa
T₁ = 345 K
P₂ = 567 Torr * 101325 Pa/760 torr = 75593.78 Pa
T₂ = 441 K
ln(75593.78 Pa/1866.51 Pa) = (-ΔHvap/8.314 J/mol·K)(1/441 K - 1/345 K)
Solving for ΔHvap,
<em>ΔHvap = 48769.82 Pa/mol or 48.77 kPa/mol</em>
Answer:
c) the study of matter and the changes it undergoes
Explanation:
Chemistry -
It is the sub topic of science , dealing with the study of matter , the properties of matter , the type of interaction between the particles of matter , the reason for the particle of matter to combine and separate in order to form new substance .
The basic concepts of chemistry are applicable on the day to day activities.
Hence, from the given options , the correct statement is c) the study of matter and the changes it undergoes.
Answer:
0.70 J/g.°C
Explanation:
Step 1: Given data
- Mass of graphite (m): 402 g
- Heat absorbed (Q): 1136 J
- Initial temperature: 26°C
- Specific heat of graphite (c): ?
Step 2: Calculate the specific heat of graphite
We will use the following expression.
Q = c × m × ΔT
c = Q / m × ΔT
c = 1136 J / 402 g × (30°C - 26°C)
c = 0.70 J/g.°C
Answer:
Hydrogen is placed above group in the periodic table because it has ns1 electron configuration like the alkali metals. However, it varies greatly from the alkali metals as it forms cations (H+) more reluctantly than the other alkali metals.
Explanation:
Answer:
The density in g/cm3 is 1.9333(put a line above the 3's to show it's repeating).
And no it is not gold because the density of gold in g/cm3 is 19.3.
Explanation:
Divide the mass by the volume in order to get an object's Density.
so, 23.2 divided by 1.20 mm3
=1.93333333 g/cm3
That is the density then you find out the density of gold in grams per cubic centimeter, that is 19.3 g/cm3
For example, gold will always have a density of 19.3 g/cm3; if a mineral has a density other than that, it isn't gold.
