Given that
z₁ = 15 (cos(90°) + i sin(90°))
z₂ = 3 (cos(10°) + i sin(80°))
we get the quotient z₁/z₂ by dividing the moduli and subtracting the arguments:
z₁/z₂ = 15/3 (cos(90° - 10°) + i sin(90° - 10°))
z₁/z₂ = 5 (cos(80°) + i sin(80°))
so that z₁ is scaled by a factor of 1/3 and is rotated 10° clockwise.
Step-by-step explanation:
f(x) = y = -1/2 × sqrt(x + 3), x >= -3
-2y = sqrt(x + 3)
4y² = x + 3
x = 4y² - 3
and now we need to rename x to y and y to x to make it a "normal" function :
y = 4x² - 3
since in the original function x >= -3, this gave us y <=0.
and therefore (remember the x of the inverse function actually stands for the y of the original function) the limit for the inverse function is x <= 0.
so, again, the full answer is
f^-1(x) = 4x² - 3, x <= 0
Answer: Angles C and E are same side interior angles.
Step-by-step explanation:
The results of the experiment are shown in the frequency side
a) 14
b) 3600 Best guess 300*12