A figure is transformed by T (x,y) = (x+3,y-1) and then transformed by S (x-3,y+1). How does the pre image relate to the final i

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2 years ago

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mage?

1 answer:

iVinArrow [24] · Answer 1 · 2023-12-25T16:45:46+03:00

the image and the pre-image are the same thing, which means that T and S are inverse operations.

<h3>How does the pre-image relate to the final image?</h3>

Here we have two transformations:

T(x, y) = (x + 3, y - 1)

S(x,y) = (x - 3, y + 1).

Now, let's start with a point (x, y), we will apply T first:

T(x, y) = (x + 3, y - 1)

Now our point is (x + 3, y - 1), and at that point, we apply the transformation S.

S(x + 3, y - 1) = (x + 3 - 3, y -1 + 1) = (x, y)

So the image and the preimage are the same thing, which means that T and S are inverse operations.

If you want to learn more about transformations:

#SPJ1