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Mice21 [21]
2 years ago
10

The midpoint of AB is M(-3, 0). If the coordinates of A are (1,-4), what are the coordinates of B?

Mathematics
1 answer:
zimovet [89]2 years ago
7 0

Using the given information, the coordinates of B are (-7, 4)

<h3>Midpoint of a Line </h3>

From the question, we are to determine the coordinates of B.

Given a line with endpoints (x₁, y₁) and (x₂, y₂), then the midpoint of the line is

((x₁+x₂)/2, (y₁+y₂)/2)

From the given information,

The midpoint of AB is M(-3, 0)

and

The coordinates of A are (1,-4)

Let the coordinates of B be (x₁, y₁)

Then,

-3 = (1 + x₁)/2

-6 = 1 + x₁

x₁ = -6 -1

x₁ = -7

Also,

0 = (-4 + y₁)/2

0 = -4 + y₁

y₁ = 0 + 4

y₁ = 4

Hence, the coordinates of B are (-7, 4)

Learn more on Midpoint of a line here: brainly.com/question/18315903

#SPJ1

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alex41 [277]

Answer:

A  16°

B  -8°

C  6°

D  -16°

E  -4°

Step-by-step explanation:

Look at 0° and 10°. There are 5 lines from one to the other, so each line represents 2°.

A

3 lines above 10° = 10° + 3 * 2° = 10° + 6° = 16°

B

1 lines above -10° = -10° + 2° = -8°

C

3 lines above 0° = 0° + 3 * 2° = 0° + 6° = 6°

D

2 lines above -20° = -20° + 2 * 2° = -20° + 4° = -16°

E

3 lines above -10° = -10° + 3 * 2° = -10° + 6° = -4°

6 0
3 years ago
Let y be inversely proportional to x. if x​ doubles, what happens to​ y?
Mila [183]
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This means; 

y=k/x (where k is a constant number like 1 or 2, etc) 

If you double x, the value of y is halved. I have attached a graph that shows this. 

Hope I helped :) 

4 0
3 years ago
Luis wants to know how much he will have available to spend on his trip to Belize in three years if he deposits $2700 today at a
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8 0
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Step-by-step explanation:

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If A+B= 45° then prove that: tanA+ tanB+ tanA. tanB​
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Answer:

See Explanation

Step-by-step explanation:

A+B= 45 \degree \\  \\ assuming  \:  \tan \: on \: both \: sides \\  \\\implies \: \tan( A+B)=  \tan 45 \degree \\  \\  \implies \: \tan( A+B)=  1 \:  \: \\  (  \because \: \tan 45 \degree = 1) \\  \\ \implies \:  \frac{\tan \: A +\tan \: B }{1 - \tan \: A .\tan \: B }  = 1 \\  \\ \implies \: \tan \: A +\tan \: B = 1 - \tan \: A .\tan \: B \\  \\ \purple{ \implies }\:  \orange{ \bold{\tan \: A +\tan \: B  + \tan \: A .\tan \: B= 1 }} \\  \\ thus \: proved

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