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zzz [600]
3 years ago
14

Kim is solving a quadratic trinomial equation and has correctly factored it into (x+3)(x-2)=0.

Mathematics
1 answer:
s2008m [1.1K]3 years ago
3 0
Hello,

Answer A
================

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The list price after commission would be $954,000.
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4 years ago
3=3(x-5)-3(x-6) what is the answer to this linear equation
lyudmila [28]

Answer:

x=0

Step-by-step explanation:

3=3(x-5)-3(x-6)

3=3x-15-3x+18

3+15-18=3x-3x

18-18=0x

0=0x

x=0

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Read 2 more answers
Matthew is making a sequence in which -3 is added to each successive term. The 6th term in his sequence is -1. What is the 1st t
Hatshy [7]

Answer:

The first term is 14.

Step-by-step explanation:

The general formula for this kind of sequence (arithmetic) is a(n) = a(1) + (n-1)c, where c is the common difference.  Here, we have a(6) = -1 = a(1) + (6-1)(-3), or -1 +15 = a(1).  The first term is 14.



3 0
3 years ago
Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form.
Georgia [21]

Answer:

D

Step-by-step explanation:

First, let's find <em>x</em>.

We know that one of the angles is 30. The side opposite to than angle is 11, and <em>x</em> is the adjacent side to it. Therefore, we can use the trig function tangent.

Recall that:

\tan(x)=opp/adj\\

Plug in 30 for the angle, 11 for the opposite, and <em>x</em> for the adjacent. Solve for <em>x</em> by cross-multiplying:

\tan(30)=11/x\\x\tan(30)=11\\x=11/\tan(30)

From the unit circle, recall that tan(30) is equal to one over the square root of 3. Thus:

x=11/(1/\sqrt3)\\x=11\cdot\sqrt3\\x=11\sqrt3

Now, we can use the Pythagorean Theorem to find <em>y</em>. <em>y</em> is the hypotenuse. Thus:

c^2=a^2+b^2\\c^2=(11\sqrt3)^2+11^2\\c^2=121(3)+121\\c^2=4(121)\\c^2\sqrt{4(121}=2(11)=22

6 0
3 years ago
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