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mestny [16]
2 years ago
9

Can Hippodamia convergens and Hippodamia variegata can mate and produce fertile offspring? Explain your answer.

Biology
1 answer:
borishaifa [10]2 years ago
8 0

Hippodamia convergens and Hippodamia variegata can mate but cannot produce fertile offspring because the number of chromosomes can make the development of the embryo unfeasible.

<h3>What are fertile hybrids?</h3>

The crossing between plants or animals of similar species can generate beings that, despite being hybrids, are fertile, even though in the initial phase of cell multiplication some chromosomes do not find the respective pair.

<h3>Why don't hybrids reproduce?</h3>

These differences in the number of chromosomes can make the development of the embryo unfeasible, as the alignment of equivalent chromosomes from the female and the male is necessary for the division of the fertilized cell to occur. When this alignment does not occur, the cell does not reproduce and dies.

With this information, we can conclude that Hybrid animals are beings from genetic crosses between different species, but of the same genus, that is, when two different animals cross and a new animal appears, usually sterile, due to their incompatible genes: the hybrid animal.

Learn more about hybrid animal in brainly.com/question/15362550

#SPJ1

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3 years ago
What is the magnitude of the force exerted by the biceps fbiceps? What is the magnitude of the force exerted by the elbow felbow
Slav-nsk [51]

Answer:

<u> </u><u>The magnitude of the force exerted by the biceps </u>f_b_i_c_e_p_s<u> is 218.38N</u>

<u>The magnitude of the force exerted by the elbow </u>f_e_l_b_o_w<u> is 194.37N</u>

Explanation:

Firstly , lets calculate the magnitude of force exerted by biceps f_b_i_c_e_p_s -

Mass of the forearm=

m_f=1.50kg

Mass of the ball =

m_b_a_l_l=950g

   = 0.950kg

so, weight of the forearm=

w_f=m_f g

weight of the ball=

w_b_a_l_l=m_b_a_l_l g

Now , balancing torque about the elbow , we have-

F_b_i_c_e_p_s\times d_b_i_c_e_p_s= w_f\times\frac{d_b_a_l_l}{2} + w_b_a_l_l\times d_b_a_l_l

(here , distance of the bicep is 2.50cm = 0.025m and distance of the ball is 36cm= 0.36m)

Now putting the given values in the formula -

F_b_i_c_e_p_s\times 0.025= 0.95\times9.8\times\frac{0.36}{2} +1.50\times 0.36

F_b_i_c_e_p_s=218.38N

Now, lets calculate the force exerted by elbow F_e_l_b_o_w -

Balancing the vertical forces

F_b_i_c_e_p_s=F_e_l_b_o_w+w_f+w_b_a_l_l

F_e_l_b_o_w = 218.38-(1.00\times9.8)-(0.95\times9.8)

F_e_l_b_o_w=194.37N

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3 years ago
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Answer: Platelets release a vasoconstricting substance called <u>SEROTONIN.</u>

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2 years ago
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Answer:

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