Answer:
Option (4). y = 3x - 5
Step-by-step explanation:
Given question is incomplete; here is the complete question.
What is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)?
y = –1/3x + 5
y = –1/3x + 3
y = 3x + 2
y = 3x − 5
Line given in the graph passes through the points (-3, 2) and (0, 1).
Slope of the given line = 
m = 
m = 
Let the equation of a line perpendicular to this line is,
y - y' = m'(x - x') [Given line passes through (x', y')]
By the property of perpendicular lines,
m × m' = -1
(
) × m' = -1
m' = 3
Equation of the perpendicular line will be,
y - 4 = 3(x - 3)
y - 4 = 3x - 9
y = 3x - 5
Option (4) will be the answer.
115.000 cents / 4 = 287.500 cents
This makes 28.75$ each person
Answer:
Kindly check explanation
Step-by-step explanation:
Verbal:
Score, x = 560
Mean, m = 460
Standard deviation, s = 132
Quantitative :
Score, x = 740
Mean, m = 452
Standard deviation, s = 140
a)
Verbal :
X ~ N(460, 132)
Quantitative :
X ~ N(452, 140)
(b)
What is her Z score on the Verbal Reasoning section? On the Quantitative Reasoning section? Draw a standard normal distribution curve and mark these two Z scores.
Zscore = (x - m) / s
Verbal :
Zscore = (560 - 460) / 132 = 0.758
Quantitative :
Zscore = (740 - 452) /140 = 2.057
(c.)
He has a higher standardized score in the quantitative than the verbal score.
(d.)
The Zscore shows that he performed better in the quantitative reasoning than verbal.
(e) Find her percentile scores for the two exams.
(f) What percent of the test takers did better than her on the Verbal Reasoning section? On the Quantitative Reasoning section?
Verbal :
Score greater than 560
P(x > 560) :
Z = (560 - 460) / 132 = 0.758
P(Z > 0.758) = 0.22423 = 22.4%
Quantitative :
Score greater than 740
P(x > 740) :
Z = (740 - 452) / 140 = 2.057
P(Z > 0.758) = 0.0198 = 1.98%
So i drew 12 circles and 37 circles
And i got 49 total:D
i hope this helps and sorry that the pic is wierd:(
Greatest Common Factor of 42 and 84. Greatest common factor (GCF) of 42 and 84 is 42.