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2 years ago

What is the answer to this equation?

Mathematics

1 answer:

My name is Ann [436]2 years ago

4 0

Answer:W ^10

Step-by-step explanation:

The solution is in the

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1.9s+6=3.1-s can you help me with this, thank you

Airida [17]

Steps:
1.9s + 6 = 3.1 - s
2.9s + 6 = 3.1
2.9s = -2.9
s = -1

8 0

3 years ago

What is the formula for a Arithmetic series and how can you use it in a practical situation? Show explanation!

SVETLANKA909090 [29]

A finite geometric series is that where the consecutive terms have a fix ratio.

Call r the ratio, An the nth term and An+1 the next term to n, then:

An+1 / An = r

For example, the geometric series, 1, 3, 9, 27, 81, ..

You can verify that

3 = 1* 3

9 = 3 * 3

27 = 9 * 3

81 = 27 * 3

So, the formula is An+1 = An * r, so if you know the first term you can find any other term.

For example, Find the fifth term of a geometric series where the first term is 5 and the second term is 25.

r = second term / first term = 25 / 5 = 5

=> Fifth term = First term * r * r * r * r = First term * r^4 = 25 * 5^4 = 15,625

From this you can also see this valid formula:

An = A1 * r^ (n-1).

So now you have two equivalent formulas:

An+1 = An * r, which is called recursive formula, and

An = A1 * r ^ (n-1), which is called explicit formula

hope this helps :)

3 0

3 years ago

Estimate the quotient of 5397÷62

Levart [38]

<span>5397 ÷ 62</span>≈<span> 5400 </span>÷ 60 =540 ÷ 6 = 90

4 0

4 years ago

The bed of a truck is stacked with with boxes of paper. The boxes are stacked 5 boxes deep by 4 boxes high by 4 boxes across

marysya [2.9K]

Answer:

Step-by-step explanation:

The boxes are stacked 5 boxes deep by 4 boxes high by 4 boxes across, then there are $5\cdot 4\cdot 4=80$ boxes in total.

The mass of 1 box of paper is 22.5 kilograms, so 80 boxes weigh $22.5\cdot 80=1800$ kilograms.

When the driver is in the truck, the mass is 2948.35 kilograms, then the total mass is

$2948.35+1800=4748.35\ kg.$

Let n be the number of boxes of paper the driver must deliver at the first stop. Their weigth is 22.5n kg and the weight of the truck without n boxes is

$4748.35-22.5n\ kg.$

Trucks with a mass greater than 4700 kilograms are not allowed over the bridge, thus

$4748.35-22.5n48.35,\\ \\n>\dfrac{967}{450}=2\dfrac{67}{450}.$

Hence, the driver must deliver at least 3 boxes at the first shop.

8 0

3 years ago

It takes 65 inches of ribbon to make a bow and wrap a ribbon around the box. The bow takes 30 inches of ribbon. The width of the

damaskus [11]

ok so the bow and the width of the box takes 42 inches of ribbon so you have 23 inches of ribbon left. take away another 12 inches for the other side of the box then you have 11 inches of ribbon left. so it takes 5 1/2 inches of ribbon to do the height on each side of the box

hope this helps my queen <3 :) ❤❤❤❤❤

3 0

3 years ago

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