18 < x ≈42
=Z and 5 (less than equal to sign) 27
= X and 2 > 50
Machine A will take 28 minutes to produce 2100 fishing lures while machine B will take 42 minutes to produce 2100 fishing lures
Step-by-step explanation:
Fishing lures per minute produced by Machine A = 75
Fishing lures per minute produced by Machine B = 50
How long will it take both machines running to produce 2100 fishing lures?
Solving For Machine A:
75 fishing lures produced by machine A = 1 minute
1 fishing lures produced by machine A = 1/75 minute
2100 fishing lures produced by machine A = 1/75*2100
= 28 minutes.
Solving For Machine B:
50 fishing lures produced by machine A = 1 minute
1 fishing lures produced by machine A = 1/50 minute
2100 fishing lures produced by machine A = 1/50*2100
= 42 minutes.
So, Machine A will take 28 minutes to produce 2100 fishing lures while machine B will take 42 minutes to produce 2100 fishing lures
Keywords: Word Problems:
Learn more about Word Problems at:
#learnwithBrainly
Let the boxes be Box 1, Box 2, Box 3.
consider the 3 white balls. They can be all of them in one box:
(3, 0, 0) (3 in Box 1, 0 in box 2 and 0 in box 0)
(0, 3, 0)
(0, 0, 3)
We can have 2 in one box, and 1 in one of the remaining boxes:
(2, 0, 1)
(2, 1, 0)
(0, 2, 1)
(1, 2, 0)
(0, 1, 2)
(1, 0, 2)
and there is only one way: (1, 1, 1) to place one white ball in each box
In total there are: 3+6+1=10 ways to place the white balls. Similarly there are 10 ways to place the black ones.
Since every placement of the white balls can be combined with any placement of the black balls, there are 10*10=100 ways to place the 3white balls and the 3 black bals in the boxes.
Answer: 100
Answer:
11
Step-by-step explanation:
30-2(7+2)-1
PEMDAS says parentheses first
30-2(9)-1
Then multiply
30 -18 -1
Then subtract
12-1
11
He gets 12$/hr so
114/12=9.5 you can check my multiplying 12 and 9.5 which is 114 so H=9.5 or 9hr30min
