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Nookie1986 [14]
1 year ago
14

I need help with this. What is the answer? (13 x 4 +5²) - 2

Mathematics
1 answer:
Fittoniya [83]1 year ago
7 0

Answer: 75

Step-by-step explanation:

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X + 6<br> for<br> &lt;1<br> f(x) =<br> -5<br> for<br> X = 19<br> X + 4<br> for<br> Find f(1)
Rzqust [24]

Answer:

Step-by-step explanation:

when, for each x in the domain of f, f(x) 6. A function f Skills and Applications 回避回Domain, Range, and Values of a is , 13. Function In Exercises 7-10, use the graph of the function to find the domain and range of f and each function value. 7. (a) f(-1) (b) f(0) 8. (a) f(-1) (b) f(0 15. f(x) 16. f(x) 17. f(x) 18. f(x) 19. f(x 4-2 2 4 6 (c) f(3) (d) f(-1)(c) f(0 (d) f(2) y | y =f(x) 20. f(x 4 2 21. f(x 22. f(x 23. f(a 24. f( 2 回 回Vertical Line Test for Functions In 25. f Exercises 11-14, use the Vertical Line Test to determine whether the graph represents y as a function of x. To print an enlarged copy of Graph the graph, go to MathGraphs.com. 窝 (a) use

8 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
Tia made a scale drawing of the White House for her history project. The actual length of the building is 168 feet, and its widt
nordsb [41]
The answer is c because I took a great guess im putting the answer because I know no-one else would put the answer for this person when they need the answer but I need the answer so I took a great guess
4 0
3 years ago
Read 2 more answers
Round $56.29 to the nearest dollar.
jeka57 [31]

Answer:

$56

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Hey can anyone help me with this question please and thank you
Ede4ka [16]

Answer:

(x-17)+(7x+5)=180

8x-12=180

8x=192

x=24

Step-by-step explanation:

5 0
2 years ago
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