Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Add up all the like terms and equal it to 720. Solve, the answer you get is x. Next subtract (x-20) and that's the answer.
Answer: OPTION C.
Step-by-step explanation:
1. The domain of the function given in the problem are all those values for which the function that is in the denomiantor is different from zero, because the division by 0 is not allowed.
2. You can make the denominator equal to zero and solve it, as you can see below:
3. Therefore, the domain is:
(-∞,0)U(0,1)U(1,∞)
Answer:
you must understand the formal
and then take a step to solve the question you are giving for example when you are given to fine √81.first you must understand what they are you to do
The answer is -2f -24.
All you gotta do is is combine like terms.
Explanation:
-2.4f + 0.4f = -2f
-16 -8 = -24
