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2 years ago

Rewrite x5/6 divided by x1/6 in simplest radical form

Mathematics

1 answer:

lisabon 2012 [21]2 years ago

5 0

5/6 and 1/6 are exponents to X. The X’s are divided by each other. does that make sense?

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Match The Following, 26 POINTS HELP FAST

zavuch27 [327]

The formula for the volume of a cone is:

$1/3\pi r^{2} h$

The formula for the volume of a cylinder is:

$\pi r^2h$

The formula for the volume of a triangular prism is:

$bh$

The formula for the volume of a pyramid is:

$1/3bh$

The formula for the volume of a rectangular prism is:

$lwh$

6 0

2 years ago

Read 2 more answers

Suppose that Upper X has a discrete uniform distribution f left-parenthesis x right-parenthesis equals StartLayout left-brace1st

emmasim [6.3K]

Answer:

the probability that the sample mean is greater than 2.1 but less than 2.4 is 0.2444

Step-by-step explanation:

Given the data in the question;

x f(x) xp(x) x²p(x)

1 1/3 0.33333 0.33333

2 1/3 0.66667 1.33333

3 1/3 1.00000 3.0000

∑ 2.0000 4.6667

∑(xp(x)) = 2

∑(x²p(x)) = 4.6667

Variance σ² = ∑(x²) - ∑(x)² = 4.6667 - (2)² = 4.6667 - 4 = 0.6667

standard deviation σ = √variance = √0.6667 = 0.8165

Now since, n = 33 which is greater than 30, we can use normal approximation

for normal distribution z score ( x-μ)/σ

mean μ = 2

standard deviation = 0.817

sample size n = 33

standard of error σₓ = σ/√n = 0.817/√33 = 0.1422

so probability will be;

p( 2.1 < X < 2.4 ) = p(( 2.1-2)/0.1422) < x"-μ/σₓ < p(( 2.4-2)/0.1422)

= 0.70 < Z < 2.81

= 1 - ( 0.703 < Z < 2.812 )

FROM Z-SC0RE TABLE

= 1 - ( 0.25804 + 0.49752 )

= 1 - 0.75556

p( 2.1 < X < 2.4 ) = 0.2444

Therefore, the probability that the sample mean is greater than 2.1 but less than 2.4 is 0.2444

7 0

3 years ago

Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

3 years ago

20 points, asap please!

devlian [24]

H(x)=-3,1 I think hope this helps

4 0

3 years ago

Read 2 more answers

How many ways can the numbers 1-100 be arranged

ra1l [238]

Answer: 5 times

Step-by-step explanation:

6 0

2 years ago