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storchak [24]
1 year ago
15

Most spyware programs are benign in that they do not perform malicious acts or steal data. group of answer choices true false

Computers and Technology
1 answer:
inessss [21]1 year ago
3 0

The statement 'most spyware programs are benign in that they do not perform malicious acts or steal data' is false.

In the field of computer studies, spyware is malicious software that is installed inside a system without the knowledge of the user. Such an act is done either to harm the data in the system or to steal information from the system. Spywares invade the privacy of a user and can lead to harmful results.

Spyware can be a serious threat to internet users as it can even track the login credentials of a user. Hence, spyware is not at all benign as it can impose serious threats to a user. Malicious activities and stealing of data are done through spyware.

To learn more about spyware, click here:

brainly.com/question/21507976

#SPJ4

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Kipish [7]

Answer:

Option d) B is 1.33 times faster than A

Given:

Clock time, t_{A} = 100 ps

t_{A} = 150 ps

No. of cycles per instructions,  n_{A} = 2.0

n_{B} = 1.0

Solution:

Let I be the no. of instructions for the program.

CPU clock cycle, f_{A} = 2.0 I

CPU clock cycle, f_{B} = 1.0 I

Now,

CPU time for each can be calculated as:

CPU time, T = CPU clock cycle\times clock time

T_{A} = f_{A}\times t_{A} = 2.0 I\times 100 = 200 I ps

T_{B} = f_{B}\times t_{B} = 1.0 I\times 100 = 150 I ps

Thus B is faster than A

Now,

\frac{Performance of A}{Performance of B} = \frac{T_{A}}{T_{B}}

\frac{Performance of A}{Performance of B} = \frac{200}{150}

Performance of B is 1.33 times that of A

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