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1 year ago

F(x) = -x+5, solve for x when f (x) =-10

Mathematics

2 answers:

MA_775_DIABLO [31]1 year ago

6 0

-x + 5 = -10
-x = -10-5
-x= -15
then x = 15
-(15)+5= -10

Delvig [45]1 year ago

5 0

Answer:

x=15

Step-by-step explanation:

-x+5

-15+5

= 10

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What is the solution: 256x + 2 = 43x + 9

ruslelena [56]

Answer:

$x = \bf \frac{7}{213}$

Step-by-step explanation:

To find the solution to the equation, we have to rearrange the equation to make $x$ the subject:

$256x + 2 = 43x + 9$

⇒ $256x + 2 - 2 = 43x + 9 - 2$ [Subtracting 2 from both sides]

⇒ $256x = 43x + 7$

⇒ $256x - 43x = 43x + 7 - 43x$ [Subtracting $43x$ from each side]

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⇒ $\frac{213}{213}x = \frac{7}{213}$ [Diving both sides by 213]

⇒ $x = \bf \frac{7}{213}$

3 0

1 year ago

Read 2 more answers

What is 2 1/3 multiplied by 5 3/5 as a mixed number or fraction

konstantin123 [22]

Answer:

13 1/15 or 196/15.

Step-by-step explanation:

First convert the mixed numbers to improper fractions.

7/3*28/5

The multiply the numerators and the denominators.

7*28=196, 3*5=15: 196/15

Hope this helps! :P

8 0

3 years ago

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Alexxx [7]

Answer:

Step-by-step explanation:

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2 years ago

Can someone help me?

shusha [124]

B. $\sqrt{x} + \sqrt{x - 1}$ ✅

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

$\frac{1}{ \sqrt{x} - \sqrt{x - 1} } \\ \\= \frac{1}{ \sqrt{x} - \sqrt{x - 1} } \times \frac{ \sqrt{x} + \sqrt{x - 1} }{ \sqrt{x} + \sqrt{x - 1} } \\ \\ = \frac{ \sqrt{x} + \sqrt{x - 1} }{ ({ \sqrt{x} })^{2} - { (\sqrt{x - 1} })^{2} } \\\\ [∵(a + b)(a - b) = {a}^{2} - {b}^{2} ] \\ \\= \frac{ \sqrt{x} + \sqrt{x - 1} }{x - (x - 1)} \\ \\= \frac{ \sqrt{x} + \sqrt{x - 1} }{ x - x + 1} \\ \\= \sqrt{x} + \sqrt{x - 1}$