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faltersainse [42]
4 years ago
14

A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at

a certain time of day, how long is the building's shadow at that time?
Mathematics
2 answers:
Angelina_Jolie [31]4 years ago
8 0

Answer: 180 feet


Step-by-step explanation:

Given: A 50-foot flagpole is at the entrance of a building that is 300 feet tall.

Them two right triangles must be formed by flagpole and building with the ground and are similar because the angle of the sun is the same at the same time of day.

So by the properties of similar triangles,

1) All the three angles of each triangle must be equal to a corresponding angle of the other triangle.

2) Sides are proportional to the corresponding sides in the other triangle,

\frac{\text{height of flagpole}}{\text{ length of flagpole's shadow }}=\frac{\text{height of building}}{\text{length of building's shadow}}\\\\\Rightarrow\frac{50}{30}=\frac{300}{\text{length of building's shadow}}\\\\\Rightarrow\text{length of building's shadow}=\frac{300\times3}{5}\\\\\Rightarrow\text{length of building's shadow}=180

Therefore, the length of building's shadow is 180 feet.


Alex Ar [27]4 years ago
8 0
The equation you can use to solve the problem is;

50/30 = 300/x

Next Cross Multiply

50x = 9000

x = 9000/50

x = 180

The building's shadow is 180 feet tall.

If this helped please Mark As Brainliest! Thanks! :)
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