All categories

2 years ago

4 more than the difference of 12 and a number j

1 answer:

7 0

The algebraic expression for the mathematical statement given as 4 more than the difference of 12 and a number j is 4 + 12 - j

<h3>How to determine the arithmetic expression?</h3>

The mathematical statement is given as:

4 more than the difference of 12 and a number j

4 more than means 4 +.

So, we have:

4 + the difference of 12 and a number j

the difference of 12 and a number j means 12 - j

So, we have

4 + 12 - j

Hence, the algebraic expression for the mathematical statement given as 4 more than the difference of 12 and a number j is 4 + 12 - j

Read more about algebraic expression at

brainly.com/question/4344214

#SPJ1

You might be interested in

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

Find the GCF of 39 and 52.

natka813 [3]

First factor each number

39=3*13

52=4*13

Now find the greatest common factor, which in our case is 13.

Answer: 13

4 0

3 years ago

Read 2 more answers

Click the picture for the question please help!!!

sesenic [268]

Answer:

297.33 m

Step-by-step explanation:

3 0

3 years ago

Solve for a<br> -8 = a(2+5)^2 +41<br> A. -1<br> B. 1<br> C. -2<br> D. 2

mario62 [17]

Answer:A

Step-by-step explanation:

-8=a(2+5)^2 + 41

-8=a x 7^2 + 41

-8=a x 7 x 7 +41

-8=49a+41

Collect like terms

-8-41=49a

-49=49a

Divide both sides by 49

-49/49=49a/49

-1=a

a=-1

5 0

3 years ago

Using the change-of-base formula, which of the following is equivalent to the

Otrada [13]

Given:

The logarithmic expression is:

$\log_718$

To find:

The equivalent expression of given expression by using change-of-base formula.

Solution:

The change-of-base formula is:

$\log_ba=\dfrac{\log_ca}{\log_cb}$

The given expression is:

$\log_718$

Using the change-of-base formula, we get

$\log_718=\dfrac{\log_c18}{\log_c7}$

Where, is a constant and c>0.

Let $c=10$ , then

$\log_718=\dfrac{\log_{10}18}{\log_{10}7}$

Therefore, the correct option is a.

3 0

2 years ago